Answer:
Philip has 1 Quarter, 3 Dimes, 5 Nickels, and 2 Pennys.
Step-by-step explanation:
Given that Philip has 11 coins that equal a total of 82 cents, and his coins include at least 1 quarter 1 dime 1 nickel and 1 penny, to determine how many of each coin does he have the following calculation must be performed:
Quarter = 0.25
Dime = 0.10
Nickel = 0.05
Penny = 0.01
0.82 - 0.25 - 0.10 - 0.05 - 0.01 = 0.41
0.41 = 0.10 x 4 + 0.1 (5 coins + 4 previous coins = 9 coins).
0.41 = 0.10 x 2 + 0.05 x 4 + 0.01 (7 coins + 4 previous coins = 11 coins).
0.25 + (3 x 0.1) + (5 x 0.05) + (2 x 0.01) = X
0.25 + 0.30 + 0.25 + 0.02 = X
0.82 = X
Thus, Philip has 1 Quarter, 3 Dimes, 5 Nickels, and 2 Pennys.
Answer:
(0,32/9)
Step-by-step explanation:
Root(2log↓3/2(2)+2,0)
Domain x∈R
Vertical Intercept (0, 32/9)
Step-by-step explanation:
d^3=d*d*d=10*10*10=1000
450=c*1000
450/1000=c
9/20=c
