1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
oee [108]
3 years ago
12

You must use the Substitution method

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0
3x+2y=5w is your answer so your main/real answer is 5w
You might be interested in
Selina claims single having one exemption. Her state tax deduction is 21% of her federal tax contribution. Calculate the amount
Maurinko [17]

Based on the number of exemptions claimed by Selina and her biweekly gross pay, her state tax will be $16.80.

<h3>How much will Selina pay for state taxes?</h3>

Selina is to pay 21% of her federal taxes.

Seeing as she claims a single exemption and falls in the $840 to $860 bracket, the table shows that her federal tax contribution would be $80.

State taxes are therefore:

= 80 x 21%
= $16.80

Find out more on withholding allowances at brainly.com/question/11308445.

#SPJ1

4 0
1 year ago
Read 2 more answers
Which question is a statistical question?
Gwar [14]

Answer:

C. How many movies do the students in my class watch in a month

Step-by-step explanation:

7 0
3 years ago
Angles relationships
amm1812

2x = 74

x = 74 ÷ 2

x = 37

that's all

7 0
3 years ago
Read 2 more answers
It costs 9.95 for 1 ticket to the movies. If 3 people go, how much would the total price of 3 tickets be?
SIZIF [17.4K]

It would be $9.95 x 3

4 0
3 years ago
Suppose a geyser has a mean time between irruption’s of 75 minutes. If the interval of time between the eruption is normally dis
lesya [120]

Answer:

(a) The probability that a randomly selected Time interval between irruption is longer than 84 minutes is 0.3264.

(b) The probability that a random sample of 13 time intervals between irruption has a mean longer than 84 minutes is 0.0526.

(c) The probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is 0.0222.

(d) The probability decreases because the variability in the sample mean decreases as we increase the sample size

(e) The population mean may be larger than 75 minutes between irruption.

Step-by-step explanation:

We are given that a geyser has a mean time between irruption of 75 minutes. Also, the interval of time between the eruption is normally distributed with a standard deviation of 20 minutes.

(a) Let X = <u><em>the interval of time between the eruption</em></u>

So, X ~ Normal(\mu=75, \sigma^{2} =20)

The z-score probability distribution for the normal distribution is given by;

                            Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean time between irruption = 75 minutes

           \sigma = standard deviation = 20 minutes

Now, the probability that a randomly selected Time interval between irruption is longer than 84 minutes is given by = P(X > 84 min)

 

    P(X > 84 min) = P( \frac{X-\mu}{\sigma} > \frac{84-75}{20} ) = P(Z > 0.45) = 1 - P(Z \leq 0.45)

                                                        = 1 - 0.6736 = <u>0.3264</u>

The above probability is calculated by looking at the value of x = 0.45 in the z table which has an area of 0.6736.

(b) Let \bar X = <u><em>sample time intervals between the eruption</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time between irruption = 75 minutes

           \sigma = standard deviation = 20 minutes

           n = sample of time intervals = 13

Now, the probability that a random sample of 13 time intervals between irruption has a mean longer than 84 minutes is given by = P(\bar X > 84 min)

 

    P(\bar X > 84 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{84-75}{\frac{20}{\sqrt{13} } } ) = P(Z > 1.62) = 1 - P(Z \leq 1.62)

                                                        = 1 - 0.9474 = <u>0.0526</u>

The above probability is calculated by looking at the value of x = 1.62 in the z table which has an area of 0.9474.

(c) Let \bar X = <u><em>sample time intervals between the eruption</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time between irruption = 75 minutes

           \sigma = standard deviation = 20 minutes

           n = sample of time intervals = 20

Now, the probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is given by = P(\bar X > 84 min)

 

    P(\bar X > 84 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{84-75}{\frac{20}{\sqrt{20} } } ) = P(Z > 2.01) = 1 - P(Z \leq 2.01)

                                                        = 1 - 0.9778 = <u>0.0222</u>

The above probability is calculated by looking at the value of x = 2.01 in the z table which has an area of 0.9778.

(d) When increasing the sample size, the probability decreases because the variability in the sample mean decreases as we increase the sample size which we can clearly see in part (b) and (c) of the question.

(e) Since it is clear that the probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is very slow(less than 5%0 which means that this is an unusual event. So, we can conclude that the population mean may be larger than 75 minutes between irruption.

8 0
3 years ago
Other questions:
  • $5 for 4 pounds of apples
    5·1 answer
  • Adriano runs a website that helps writers write better stories. Every month, Adriano receives a subscription fee of $ 5 from eac
    6·2 answers
  • Can you please help me with this please ty
    13·1 answer
  • Who can help me with 5 math questions ? yes or no, and i will give them to you.
    12·1 answer
  • Paul has $35,000 in his savings account. Each month he spends $1,800. He adds no money to the accountWrite a linear equation to
    6·2 answers
  • Triangle A is the pre-image in a translation, and triangle B is the image, as shown below.
    9·2 answers
  • What is 86% of 950? *
    7·2 answers
  • Help plz math I have pic
    13·1 answer
  • Please , answer this question:(
    14·1 answer
  • Please help, i usually know but
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!