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Valentin [98]
3 years ago
6

  Please help this is due today please i really need help it’s due in 4 hours!!!

Mathematics
2 answers:
Ugo [173]3 years ago
8 0

Answer:

x=55°

y=70°

Step-by-step explanation:

x=55°

y=180-55-55=70°

Anna35 [415]3 years ago
4 0

Answer:

x=55 y=70 j=110

Step-by-step explanation:

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G-GPE-S & G-GPE-7: Practice_2
mezya [45]

The required equation is y = -9

Step-by-step explanation:

Step 1 :

Given the line l is perpendicular to the y axis

The equation of the y axis is x = 0

So any line perpendicular to the y axis will have equation as y = k , where k is a constant value for any value of x

Step 2 :

Its given that the line is passing through the point  (0.-9). Here the y co ordinate is -9. Hence the perpendicular line has a constant y co ordinate of y = -9 for any value of x

So the required equation is y = -9

Step 3 :

Answer :

The required equation is y = -9

6 0
3 years ago
Solve 30 = −5(6n + 6), justifying each step with an algebraic property.
Liula [17]
1) property of distribution: 30 = -30n - 30
2) inverse property of addition: 60 = -30n
3) inverse property of multiplication: -2 = n

step 2: subtract 30 from both sides
step 3: divide -30 from both sides
7 0
4 years ago
Soon after taking an aspirin, a patient has absorbed 280 mg of the drug. After 2 hours, only 70 mg remain. Find an exponential m
svetlana [45]
Y = 300e^(-Bt) 
plug in y = 75 and t = 2 
75 = 300e^(-2B) 
75/300 = e^(-2B) 
ln(75/300) = -2B 
B = -ln(75/300) / 2 
so B = approx 0.693300 = A(e^0) = A 
<span>A = 300 
</span>. 9.4 mg left in the bloodstream after 5 hours. 
<span>

</span>
4 0
3 years ago
Find the slope (0.-4) and (-2,-2) help me
Dmitry [639]
The answer is -1.

You do -2- -4 and get 2.
Then do -2-0 and get -2.
The last step is to do 2 divide -2 and you get -1.
3 0
3 years ago
Please help me with this question
cricket20 [7]
They give you: <RSP = 90 degrees

If you look in the diagram, <RSP is vertical to <UPW and vertical angles have the same measure. <RSP = <UPW

So the correct answer is A.
7 0
4 years ago
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