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irina1246 [14]
3 years ago
8

Amy has saved $725 for a new guitar and lesson. Her guitar cost $475, and guitar lessons are $25 per hour. Determine how many ho

urs of lessons she can afford
Mathematics
2 answers:
luda_lava [24]3 years ago
6 0
You start with total amount ($725) and subtract guitar cost ($475) and get $250. Then you divide guitar lessons per hour ($25) and get 10. Which is the amount of lessons she  can afford
babymother [125]3 years ago
3 0
725 - 475 = 230 and 230 divided by 25 is just over 9 so 9
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geniusboy [140]
<h2><u>COMBINED OPERATIONS</u></h2><h3>Exercise</h3>

First, let's solve the subtraction (in parentheses):

\mathsf{\dfrac{-8\left(2-6\right)}{2}}

\mathsf{\dfrac{-8(-4)}{2}}

Now, let's solve the multiplication. Remember: in multiplication, two negative numbers will give a positive number:

\mathsf{\dfrac{-8(-4)}{2}}

\mathsf{\dfrac{32}{2}}

Finally, let's solve the division:

\mathsf{\dfrac{32}{2} = 16}

<h3><u>Answer</u>: 16</h3>
5 0
3 years ago
Can someone help me with this please?
Daniel [21]

Answer:

Classify by angles: <u>Equiangular</u>

Classify by sides: <u>Equilateral</u>

Step-by-step explanation:

An equiangular triangle has angles that all measure 60 degrees. An equilateral triangle is a triangle that has sides will all of the same lengths. This triangle meets both of these requirements.

Hope it helps!

5 0
3 years ago
A softball fits snuggly inside a cubical box that is 4 inches on each side. What is the volume of the softball that fits snuggly
Natali5045456 [20]

Answer:

33.5 cubic inches.

Step-by-step explanation:

If the softball fits perfectly inside the cubical box, the softball is a sphere with diameter of 4 inches (radius os 2 inches).

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V= \frac{4}{3}\pi r^3

For r = 2 inches:

V= \frac{4}{3}*3.14* 2^3\\V=33.5\ in^3

The volume of the softball is 33.5 cubic inches.

4 0
3 years ago
7. If the value of x varies directly with the value of y, and x = 3 when y = 21. What is the valu
konstantin123 [22]

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3 0
3 years ago
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If N is the population of the colony and t is the time in​ days, express N as a function of t. Consider Upper N 0 is the origina
lesya [120]

Answer:

(a)N(t)=Noe^{kt}

(b)5,832 Mosquitoes

(c)5 days

Step-by-step explanation:

(a)Given an original amount N_o at t=0. The population of the colony with a growth rate k \neq 0, where k is a constant is given as:

N(t)=Noe^{kt}

(b)If N_o=1000 and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)

Therefore, our model is:

N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t

In 3 days time

N(3)=1000\cdot1.8^3=5832

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0
3 years ago
Read 2 more answers
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