All categories

3 years ago

Items owned that can be sold for cash are known as

1 answer:

6 0

Assets are anything of value owned by a person that could easily be sold for cash. These could be property such as buildings, homes or land, or items such as cars, jewelry, boats, etc.

ANSWER: Assets are items owned that can be sold for cash.

Hope this helps! :)

You might be interested in

identify the expression as a numerical expression or a variable expression.For variable expression, name the variable 1×12

Aliun [14]

Answer:

o7 fy hk hpxi oyli ifuod pir8

5 0

3 years ago

Given that f(x)=3x+1 and g(x)=4x+2/4, solve for g(f(0))

maksim [4K]

$f(x)=3x+1\\\\g(x)=\dfrac{4x+2}{4}\\\\f(0)=3\cdot0+1=0+1=1\\\\g(f(0))=g(1)=\dfrac{4\cdot1+2}{4}=\dfrac{4+2}{4}=\dfrac{6}{4}=\dfrac{6:2}{4:2}=\dfrac{3}{2}=1.5$

7 0

3 years ago

You are making necklaces for your friends. You have 54 blue beads and 28 red beads. Each friend will recevie an identical neckla

lina2011 [118]

This is actually a bit confusing but I think you could only make a necklace for 2 people. Each person will recieve 27 blue beads, and 9 red beads. Hope this helps!

7 0

3 years ago

The above picture represents all of the following, except

Nutka1998 [239]

What is the picture?

5 0

3 years ago

I have 200 coins to put into 4 bags I put the coins into each bag so that each bag has 2 mote coins than the one before How many

Allushta [10]

First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins

Solution:

Given that,

Total number of coins = 200

Number of bags = 4

I put the coins into each bag so that each bag has 2 more coins than the one before

Therefore,

Each bag has 2 more coins than the one before. Based on this we can say,

Let "x" be the number of coins put in first bag

Then, x + 2 is the number of coins put in second bag

Then, x + 4 is the number of coins put in third bag

Then, x + 6 is the number of coins put in fourth bag

We know that,

Total number of coins = 200

$x + x + 2 + x + 4 + x + 6 = 200\\\\4x + 12 = 200\\\\4x = 200-12\\\\4x = 188\\\\x = 47$

Thus,

Coins put in first bag = x = 47

Coins put in second bag = x + 2 = 47 + 2 = 49

Coins put in third bag = x + 4 = 47 + 4 = 51

Coins put in fourth bag = x + 6 = 47 + 6 = 53

Thus number of coins in each bag are found

4 0

3 years ago