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Alinara [238K]
4 years ago
9

Which statement is correct about the system of linear equations graphed below?

Mathematics
1 answer:
zimovet [89]4 years ago
5 0

Answer:

The system of equations does not have one solution because the lines will never intersect.

Step-by-step explanation:

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for employees of Papa Tony's pizza or cleaning up at the end of a busy night. There is a list of 43 complete a task that need to
nydimaria [60]
The answer is 10r3

Hope this helps
3 0
4 years ago
The product of 216 and j, decreased by 150 is equal to 288
Scrat [10]
The equation would be:
(216 x j) - 150= 288
4 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
What is the answer? Please
ryzh [129]
D is not equivalent because it equals 4/25 y 5 I think
3 0
3 years ago
Mercury
cestrela7 [59]
It’s the sizes I’m pretty sure
4 0
1 year ago
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