The lengths of the sides of the triangle are 8, 8, 20
Explanation:
Given that the perimeter of an isosceles triangle is 36 inches.
The base of the triangle is 
times longer than each of its legs.
We need to determine the lengths of the sides of the triangle.
<u>Lengths of the sides:</u>
Let x denote the lengths of the sides of the triangle.
The base of the triangle is given by
Perimeter of the isosceles triangle = Sum of the three sides of the triangle.
Thus, we have,
Thus, the length of the sides of the isosceles triangle is 8 inches.
Base of the triangle = 
Hence, the three sides of the isosceles triangle are 8, 8, 20
Answer:
yes
Step-by-step explanation:
8705/1000 = 8705*0.001
8.705 = 8.705
Xy = 50
x + y = 15
x = 15 - y
xy = 50
(5 - y)y = 50
5y - y^2 = 50
y^2 - 5y + 50 = 0
(y - 5)(y - 10) = 0
y - 5 = 0 or y - 10 = 0
y = 5 or y = 10
x + y = 15
For y = 5:
x + 5 = 15
x = 10
For y = 10
x + 10 = 15
x = 5
Answer: the numbers are 5 and 10.
For circumference it’s 12x3.14= 37.68
Answer:
length = 14 feet
width = 6 feet
Step-by-step explanation:
A = 84 feet square
ratio of length and width = 7 : 3
total ratio of length and width 10 = a
length = (7/10)a
width = (3/10)a
A = length x width = (7/10)a x (3/10)a = (21/100)a² = 84
a² = 84 x 100 : 21 = 400
a = 20 feet
length = 7/10 x 20 = 14 feet
width = 3/10 x 20 = 6 feet
