$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-7})\qquad
(\stackrel{x_2}{7}~,~\stackrel{y_2}{4})
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{7-2}{2}~~,~~\cfrac{4-7}{2} \right)\implies \left(\cfrac{5}{2}~,~\cfrac{-3}{2} \right)\implies \left( 2\frac{1}{2}~,~-1\frac{1}{2} \right)$

5 0

3 years ago

Find the standard deviation of

Kruka [31]

Answer:

11.5

The sample standard deviation measures the spread of a data distribution of the sample. It is usually used to estimate the population standard deviation

7 0

2 years ago

The vertices of a parallelogram are A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4). Which of the following must be true if paral

d1i1m1o1n [39]

Answer:

The following points are not arranged in a parallelogram or rectangle order.

Step-by-step explanation:

Well first we need to graph the following.

A(1,1) B(2,2) C(3,3) D(4,4)

By looking at the image below we can tell it is not any shape, it’s not a parallelogram or a rectangle.

It is a line with a slope of 1 or x.