So we are given the following system:
$3x^2-4y^2=25\\
-6x^2-2y^2=11\\\text{Multiply the second equation by -2:}\\12x^2+4y^2=-22\\\text{Add to the first equation we get:}\\15x^2=3
\text{ therefore }x=\pm \sqrt{ \frac{1}{5} }$
Using the first equation again we get:
$3x^2-4y^2=25\\
3x^2=4y^2+25\\
x^2= \frac{1}{3}(4y^2+25)\\x^2= \frac{1}{3}(4 \frac{1}{5} +25)\\= \frac{43}{5}\\x=\pm \sqrt{ \frac{43}{5} }$

3 0

2 years ago

4(x − 3) − 5(x + 1) = 3 Which of the following algebraic properties is not needed to solve this equation?

skelet666 [1.2K]

Hi there!

To solve this problem, you need to use the distributive property. You distribute the 4 inside the parenthesis as well as the 5.

Hope this helps!

7 0

2 years ago