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faltersainse [42]
3 years ago
12

What type of angle is shown below? A.acute B.straight C.obtuse D.right

Mathematics
2 answers:
Serjik [45]3 years ago
8 0

Answer:

Acute

Step-by-step explanation:

its not right because its coming in. Obtuse would be bigger then a right

mars1129 [50]3 years ago
8 0
That is definitely acute! :) (Also, I would love to get brainliest!)
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The area of Russia is about 1.71 x 107 square kilometers. The area of Jamaica is about 1.10 x 104 square miles. How many times l
11111nata11111 [884]

Answer:

2 x 10^3 times

Step-by-step explanation:

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3 0
2 years ago
Use the following area model to multiply 42 x 73
Sergio [31]

A=2800,B=120,C=140,D=6

7 0
4 years ago
Is 7/8 or 11/10 closer to 1? how did you decide?
nirvana33 [79]
11/10 is closer to 1. 
To solve for this, give them common denominators. Lets make it 80 for this one.
To get 80, you multiply 8 by 10, so you have to do the same to the number on top. This gives you 70/80.
To get 80 for the second fraction, you multiply by 8 and get 88/80.
Now lets take the numbers on top and subtract them from 80. 
88 - 80 = 8
80 - 70 = 10
8 is less than 10, and so 11/10 is closer.
7 0
3 years ago
Read 2 more answers
Anisa went to Dicks Sporting good and bought
MissTica

Answer: $492

The work:

Anisa got $116

      58 x 2 = 116

Emma got $376

      94  x 4 = 376

Add them: $492

5 0
3 years ago
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A car travels 32 km due north and then 46 km in a direction 40° west of north. Find the direction of the car's resultant vector.
tatuchka [14]

Answer:

Step-by-step explanation:

This requires some serious work before we even begin. First off, we will convert the km to meters:

32 km = .032 m

46 km = .046 m

And then we have to deal with the angle given as 40 degrees west of north. An angle 40 degrees west of north "starts" at the north end of the compass and moves towards the west (towards the left in a counterclockwise manner) 40 degrees. That means that the angle that is made with the negative x axis is a 50 degree angle. BUT the way angles are measured in standard form are from the positive x-axis, therefore:

40 degrees west of north = 50 degrees with the negative x axis = 130 degrees with the positive x axis. 130 is the angle measure we use. Phew! Now we're ready to start. Adding vectors requires us to use the x and y components of vectors in order to add them.

A_x=.032cos90.0 so

A_x=0 (the 90 degrees comes from "due north")

B_x=.046cos130 so

B_x=-.030 and if we add those to get the x component of the resultant vector, C:

C_x=-.030   And onto the y components:

A_y=.032sin90.0 so

A_y=.032

B_y=.046sin130 so

B_y=.035 and if we add those together to get the y component of the resultant vector, C:

C_y=.067  Note that since C_x is negative and C_y is positive, the resultant angle (the direction) will put us into QII.

We find the magnitude of C:

C_{mag}=\sqrt{(-.030)^2+(.067)^2}

We will round this after we take the square root to the thousandths place.

C_{mag}=.073m and now for the angle:

\theta=tan^{-1}(\frac{.067}{-.030}) which gives us an angle measure of -67, but since we are in QII, we add 180 to that to get that, in sum:

The magnitude of the resultant vector is .073 m at 113°

6 0
3 years ago
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