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True [87]
3 years ago
8

Math help please?! i will love you forever!

Mathematics
1 answer:
KiRa [710]3 years ago
6 0
The transformation would be a vertical translation 4 units down and a horizontal translation 2 units left.

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Help me with my math please!!!!
astra-53 [7]

Look up "Everything You Need To Know About Math In One Big Fat Notebook pdf." It's the best thing I've ever been given, I have it with me in math class all the time and I've aced every test. I have it with me right now and it has everything I've ever been taught about math in it so it might help you.

7 0
3 years ago
Which of the following measures of variability can be used to compare two data sets? Select all that apply.3 Answers PLZ FAST AS
Ksenya-84 [330]
A B D I’m pretty sure. Median is 3 or more and range just doesn’t make sense for 2 numbers
8 0
3 years ago
Read 2 more answers
How does Shakespeare create an immediate mood of sadness around Romeo
Ber [7]

Answer:

Shakespeare creates an immediate mood of sadness around Romeo because he said sad hours go by slow. also, he talks to benvolio about how sad he is

6 0
2 years ago
Suppose that f : [a, b] → [a, b] is continuous. Prove that f has a fixed point. That is, prove that there exists c ∈ [a, b] such
nikklg [1K]

Answer:

Step-by-step explanation:

define the function:

g(x) = f(x) -x

As both f(x) and x are continuous functions, g(x) will also be continuous.

Now, what can we say about g(a) = f(a) -a?

we know that a\leq f(a) \leq b, thus:

a-a\leq f(a)-a \leq b-a\\0 \leq g(a) \leq b-a

thus  g(a) is non-negative.

What about g(b) ? Again we have:

a\leq f(b) \leq b\\a-b \leq f(b) -b \leq  0\\a-b \leq g(b) \leq  0

That means that g(b) is not positive.

Now, we can imagine two cases, either one of g(a) or g(b) is equal to zero, or none of them is. If either of them is equal to zero, we have found a fixed point! In fact, any point c for which g(c)=0 is a fixed point, because:

g(c) = 0 \implies f(c) -c = 0 \implies f(c) = c

Now, if g(a) \neq  0 and g(b) \neq 0, then we have that

g(a) >0 and g(b) < 0. And by Bolzano's theorem we can assert that there must exist a point c between a and b for which g(c)=0. And as we have shown before that point would be a fixed point. This completes the proof.

6 0
3 years ago
Determine the arc length of a circle that has a 7-centimeter radius and a central angle that is 40 degrees. Use 3.14 for π and r
agasfer [191]
Given:
Radius = 7cm
Central angle (theta) = 40 degrees

Asked:
Arc length (s)

SOLUTION:
s = 2*pi*radius*(central angle/360)
s = 2(3.14)(7cm)(40 degrees/360 degrees)
s = 4.88 cm

Therefore, the arc length of the circle is 4.88 centimeters.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.


6 0
3 years ago
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