A. 3 baskets
B. 6 oranges
C. 9 pears
D. 4 bananas
Hope this helps! Let me know if you need any further assistance!
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
x = 4
Step-by-step explanation:
8/72 = x/36
crossmultiply
8 x 36 = X x 72
288 = 72x
divide both sides by 72
288/72 = x
therefore , x = 4
Answer:
cosine i think tell me if im wrong
Step-by-step explanation:
