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garik1379 [7]
3 years ago
10

Solve for q. –10 + 10q = 9q

Mathematics
2 answers:
Kitty [74]3 years ago
6 0

Answer:

q= 10

Step-by-step explanation:

9q - 10q = -10

-q = -10

q= -10/-1 = 10

ASHA 777 [7]3 years ago
3 0

Answer:

q=10

Step-by-step explanation:

subtract 10q from both sides than divide-10 by -1

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A 24 foot ladder is placed against a building at an angle of 75⁰. How far is the bottom of the ladder from the building?
yanalaym [24]
24ft is the hypotenuse, at an angle of 75<span>⁰, and we need to find the adjacent.

We use cos(), which is adjacent divided by hypotenuse.

Therefore, we can find the adjacent by doing:

25 * cos(75) = 6.47ft

Round the answer however you like.</span>
6 0
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Find the area of the parallelogram.
Ivenika [448]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
divide 6x^4+2x^3-6x^2-14x-1 by 3x+1 by using long divison show all work then explain if 3x+1 is a factor of the dividend
dlinn [17]

After working this problem out, we know that 3x + 1 is not a total factor of the dividend, because there is a remainder.

When you divide a polynomial by another polynomial, if there is a remainder, it is not a complete factor.

<h3><u>After dividing, we are left with: 2x^3 - 2x - 4 + (3/(3x + 1))</u></h3>

There is a remainder of 3.

6 0
3 years ago
What are the side lengths of the rectangle area 40 perimeter 26
shusha [124]
Recall the formula for finding the area of a rectangle:

           Area = Length × Width

Recall the formula for finding the perimeter of a rectangle:

         Perimeter = 2 ( Length + Width )

Given in your problem:
        Area = 40 sq. units
        Perimeter = 26 units

Required to solve for:
        Length (L) and width (W)

• First, substitute the given to the formula:

        Area = Length x Width
          40 = L × W      ⇒   equation number 1

       Perimeter = 2 ( Length + Width )
            26 = 2 ( L + W )     ⇒   equation number 2


• Simplifying equation number 2,
           13 = L + W

 • Rearranging the equation, 

         L = 13 - W   ⇒   equation 3

Substituting equation 3 from equation 1:

      ( equation 1 )               40 = (L)(W)
      ( equation 3 )                L = 13 - W
                                      40 = (13 - W) (W)
                                      40 = 13W - W² 
      ( regrouping )          W² - 13W + 40 = 0
      ( factoring )             (W - 8) (W - 5) = 0
                                     W - 8 = 0    ;     W - 5 = 0
                                        W = 8      ;        W = 5
   
Therefore, there are 2 possible values for the width of the rectangle. It can be 8 units or 5 units.

• Now to solve for the length of the rectangle, substitute the two values of width to equation 3.

      (equation 3)        L = 13 - W
                       for W = 8    ⇒   L = 13 - 8
                                                   L = 5 units
                   
                       for W = 5    ⇒  L = 13 - 5
                                                   L = 8 units

3 0
3 years ago
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