The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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A equation to represent this situation is:
Now we have to find x.
Step 1: Subtract 0.5x from both sides.
<span><span><span><span>0.75x</span>+7.5</span>−<span>0.5x</span></span>=<span><span><span>0.5x</span>+10</span>−<span>0.5x</span></span></span><span><span><span>0.25x</span>+7.5</span>=10
</span>Step 2: Subtract 7.5 from both sides.
0.25x+7.5−7.5=10−7.50.25x=2.5
Step 3: Divide both sides by 0.25.
<span><span><span>0.25x/</span>0.25</span>=<span>2.5/<span>0.25
</span></span></span>Answer:
<span>x=<span>10</span></span>
They will cost the same after 10 rides.
Answer:
Step-by-step explanation:
6x^2+5x+1=0
Descr= b^2-4ac
Descr= 25-24=1
X1= (-b+√descr)/2a = (-5+1)/12= -1/3
X2= (-b-√descr)/2a = (-5-1)/12= -1/2
Answer:
Option D) is correct
That is Option D) "The diagonals bisect each other" is correct
Step-by-step explanation:
The property of all squares is
"The diagonals of a square bisect its angles" and it can be written also also as below
"The diagonals bisect each other"
Therefore Option D) is correct
That is Option D) "The diagonals bisect each other" is correct
