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horrorfan [7]
4 years ago
6

Use an area model to solve the equation 391 × 41=

Mathematics
2 answers:
Ad libitum [116K]4 years ago
8 0
The answer is 16,031.

Hope this helps! ;)
Ipatiy [6.2K]4 years ago
7 0
I dont know about the area model but answer is 16,031.
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If Matrix A is 5 x 2 and Matrix B is 3 x 5, then Matrix BA is 5 x 5.
Pie

Answer:

Correct, 25.

Step-by-step explanation:

8 0
3 years ago
Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
2 years ago
Read 2 more answers
Program X has an annual cost of $35000, and, in return, is expected to save Company C $40,000 during the first year. Assuming th
Nastasia [14]
For the answer to the question above,
<span>The program has an annual cost of $35,000 and will generate $40,000 savings the first year. 

$35,000 / $40,000 = .875
.875 x 12 months = 10.5 months
I hope my answer helped you. Feel free to ask more questions Have a nice day!</span>
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3 years ago
A physician orders 0.5oz of magnesia and alumina oral suspension antacid 4 times per day for a client with indigestion.how many
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1 fl oz. is equivalent to 29.6 ml.
0.5 * 4 * 29.6 = 59.2 ml
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3 years ago
What is the vertex of -x^2-6x-11?
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<span>the answer to this is (3,-2)</span>
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