Rolle's Theorem does not apply to the function because there are points on the interval (a,b) where f is not differentiable.
Given the function is 
and the Rolle's Theorem does not apply to the function.
Rolle's theorem is used to determine if a function is continuous and also differentiable.
The condition for Rolle's theorem to be true as:
- f(a)=f(b)
- f(x) must be continuous in [a,b].
- f(x) must be differentiable in (a,b).
To apply the Rolle’s Theorem we need to have function that is differentiable on the given open interval.
If we look closely at the given function we can see that the first derivative of the given function is:
![\begin{aligned}f(x)&=\sqrt{(2-x^{\frac{2}{3}})^3}\\ f(x)&=(2-x^{\frac{2}{3}})^{\frac{3}{2}}\\ f'(x)&=\frac{3}{2}(2-x^{\frac{2}{3}})^{\frac{1}{2}}\cdot \frac{2}{3}\cdot (-x)^{\frac{1}{3}}\\ f'(x)&=\frac{-\sqrt{2-x^{\frac{2}{3}}}}{\sqrt[3]{x}}\end](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7Df%28x%29%26%3D%5Csqrt%7B%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E3%7D%5C%5C%20f%28x%29%26%3D%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5C%5C%20f%27%28x%29%26%3D%5Cfrac%7B3%7D%7B2%7D%282-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Ccdot%20%5Cfrac%7B2%7D%7B3%7D%5Ccdot%20%28-x%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%20f%27%28x%29%26%3D%5Cfrac%7B-%5Csqrt%7B2-x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%5Cend)
From this point of view we can see that the given function is not defined for x=0.
Hence, all the assumptions are not satisfied we can reach a conclusion that we cannot apply the Rolle's Theorem.
Learn more about Rolle's Theorem from here brainly.com/question/12279222
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Answer:
3 3/8
Step-by-step explanation:
We assume your intended question is ...
"Find the actual sum of 1 3/4 + 1 5/8 to determine how much David grew in two years. Explain ..." (Proper word choice and punctuation help communication.)
The sum of the two given mixed numbers can be found several ways. One way is to write the fractions using a common denominator:
1 3/4 + 1 5/8 = 1 6/8 + 1 5/8 = (1 +1) +(6/8 +5/8) = 2 + 11/8 = 3 3/8
David grew 3 3/8 in two years.
__
Both numbers are near and slightly more than 1.5, so their sum will be near and slightly more than 3.
<span>1C. 5^3 = 125 mL
2A. 30^3 = 27,000 mL = 27 L
3D. 75 mm is 7.5 cm, so we do: 7.5^3 = 421.875 mL = 0.421875 L =~ 0.422 L
Note:
1 mL = 1 cm^3
1 L = 1,000 mL
10 mm = 1 cm</span>
Answer:
20%
Step-by-step explanation:
We can start by looking at it as a ratio, so 4 divided by 20 and 4/20 = 0.2, so that would be 20% viewing 1=100%.
Another way is
20 here is 100%, and for 20 to equal 100, we have to multiply it by 5. To balance it out, multiply the top by 5 as well, and 4 * 5 =20. Therefore, 4/20 = 20%
