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ollegr [7]
3 years ago
11

Given that J is between H and K. If JK=3x-1, HJ=2x+4, and HK=12, find x and JK.

Mathematics
2 answers:
cricket20 [7]3 years ago
5 0

Answer:

X=7

Step-by-step explanation:

HJ + JK = HK

3(X + 2) +(3X - 4) = 44

3X + 6 + 3X - 4 = 44

6X + 2 = 44

6X = 42

X = 7

Naddika [18.5K]3 years ago
5 0

Answer:

x=1.8   JK=4.4

Step-by-step explanation:

JK+HJ=HK

3x-1+2x+4=12

5x+3=12

5x=9

x=1.8

JK=3x-1

JK=3(1.8)-1

JK=5.4-1

JK=4.4

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The cost to produce a product is modeled by the function f(x) = 5x2 − 70x 258, where x is the number of products produced. compl
ad-work [718]

The minimum cost to produce the product is $7.

What are functions?

  • A function from a set X to a set Y allocates exactly one element of Y to each element of X.

To determine the minimum cost:

We have to determine the minimum cost of producing this product.

Since f(x) = 5x^{2} -70x+258.

Now, consider the equation 5x^{2} -70x+258= 0.

Dividing the above equation by 5, we get

x^{2} -70x/5+258/5=0\\x^{2} -14x+258/5=0

Now, considering the coefficient of 'x', dividing it by '2' and then adding and subtracting the square of the number which we got after dividing.

Since the coefficient of 'x' is 14, and half of 14 is '7'.

So, adding and subtracting from the above equation.

x^{2} -14x+(7)^{2} -(7)^{2}+258/5=0\\x^{2} -14x+49 -49+258/5=0\\(x-7)^{2} -49+258/5=0\\(x-7)^{2} +258-245/5=0\\(x-7)^{2} +13/5=0\\5(x-7)^{2} +13=0

Now, we have to determine the minimum cost to produce the product.

Since f(x) = 5x^{2} -70x+258.

f'(x) = 10x-70

Now, let f'(x)=0

10x-70=0\\10x=70

Therefore, x=7

Now, consider which is greater than 0.

Therefore, x= 7 is the minimum cost.

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Read 2 more answers
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