if a > 0, there are two possible solutions:
the square root of a square is the base in absolute value bars
if a = 0, that means x = 0. anything multiplied by 0 is 0
if a < 0, there are no solutions because anything squared has to be positive
Given that J is between H and K. If JK=3x-1, HJ=2x+4, and HK=12, find x and JK.
2 answers:
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