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ollegr [7]
4 years ago
11

Given that J is between H and K. If JK=3x-1, HJ=2x+4, and HK=12, find x and JK.

Mathematics
2 answers:
cricket20 [7]4 years ago
5 0

Answer:

X=7

Step-by-step explanation:

HJ + JK = HK

3(X + 2) +(3X - 4) = 44

3X + 6 + 3X - 4 = 44

6X + 2 = 44

6X = 42

X = 7

Naddika [18.5K]4 years ago
5 0

Answer:

x=1.8   JK=4.4

Step-by-step explanation:

JK+HJ=HK

3x-1+2x+4=12

5x+3=12

5x=9

x=1.8

JK=3x-1

JK=3(1.8)-1

JK=5.4-1

JK=4.4

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Hello,
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line 2: (-3,1), (3,3)==>y-1=(x+3)2/6==> x-3y=-6 (2)

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3 years ago
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TEA [102]
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