1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jolli1 [7]
3 years ago
10

Pls help your going to help my dead soulll

Mathematics
1 answer:
deff fn [24]3 years ago
4 0
0.875 seconds
Can you give me brainliest please
You might be interested in
The directions says determine weather each rate of change is consistent. If it is, find the rate of change and explain what it r
Whitepunk [10]

3:1 is your answer bruuuuuuhhhh

4 0
2 years ago
Read 2 more answers
Can someone plz help me with this one problem!!!!
Anarel [89]

Answer:

its 63..................

5 0
2 years ago
Read 2 more answers
A painter takes 2 3/5 hours to paint a wall. How many hours will the painter take to paint 8 walls if she works at the same rate
Naya [18.7K]
2 3/5 X 8 = 20.8 hours

7 0
3 years ago
Read 2 more answers
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
Need to find Value of x
Pie
180 = 3x + 5x + 2x +5
180 = 10x + 5
175 = 10x
x = 17.5

180 is how many degrees in a triangle
4 0
3 years ago
Other questions:
  • You are a member of your local movie theater’s club. Every time you see a movie at the theater, you earn 2 advantage points. Whe
    5·1 answer
  • If f(x)= x^2 which of the following describes the graphs of f(x) +4
    12·1 answer
  • (y 3 - 4y 2 + 7y - 6) (y - 2)
    14·1 answer
  • What is the formula to a trapezoid
    10·1 answer
  • Gina is putting books on a shelf that is 21 2⁄3 inches long. If each book is 2 1⁄3 inch wide, how many books can she fit on the
    5·1 answer
  • What is the end behavior of the function f(x)=5/4x^2
    6·1 answer
  • Plzzz show me how you got it a Decimal form​
    7·2 answers
  • Which statement are true regarding undefinable terms in geometry
    14·1 answer
  • What is the first step when examining a data set? *
    7·1 answer
  • PLS HELP!!! WILL MARK BRAINLIEST!!
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!