Answer:
Step-by-step explanation:
Hello!
The variable of study is X: Temperature measured by a thermometer (ºC)
This variable has a distribution approximately normal with mean μ= 0ºC and standard deviation σ= 1.00ºC
To determine the value of X that separates the bottom 4% of the distribution from the top 96% you have to work using the standard normal distribution:
P(X≤x)= 0.04 ⇒ P(Z≤z)=0.04
First you have to use the Z tables to determine the value of Z that accumulates 0.04 of probability. It is the "bottom" 0.04, this means that the value will be in the left tail of the distribution and will be a negative value.
z= -1.75
Now using the formula of the distribution and the parameters of X you have to transform the Z-value into a value of X
z= (X-μ)/σ
z*σ = X-μ
(z*σ)+μ = X
X= (-1.75-0)/1= -1.75ºC
The value that separates the bottom 4% is -1.75ºC
I hope this helps!
If the problem is supposed to read (4^33*8^37)/(4^15*8^21), then...
(4^33*8^37)/(4^15*8^21) = (4^33/4^15)*(8^37/8^21)
(4^33*8^37)/(4^15*8^21) = 4^(33-15)*8^(37-21)
(4^33*8^37)/(4^15*8^21) = 4^18*8^16
Answer: Choice A) 4^18*8^16
Answer:
x=0 or x=−4
Step-by-step explanation:
Let's solve your equation step-by-step.
(x+2)2=4
Step 1: Simplify both sides of the equation.
x2+4x+4=4
Step 2: Subtract 4 from both sides.
x2+4x+4−4=4−4
x2+4x=0
Step 3: Factor left side of equation.
x(x+4)=0
Step 4: Set factors equal to 0.
x=0 or x+4=0
x=0 or x=−4
Answer:
4 mi/h
Step-by-step explanation:
The distance between the cyclists is the hypotenuse of an isosceles right triangle. The hypotenuse is √2 times the length of the legs in such a triangle, so each cyclist must have ridden 8 miles in 2 hours.
Their speed is (8 mi)/(2 h) = 4 mi/h.
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<em>Additional comment</em>
Consider an isosceles right triangle with leg lengths 1. Then the Pythagorean theorem tells us the length of the hypotenuse is ...
c² = a² +b² . . . square of hypotenuse is sum of squares of legs
c² = 1² +1² . . . . both legs are 1 in our example triangle
c² = 2
c = √2
That is, the hypotenuse is √2 times the leg length.
The first 3 , after 2 and 6
