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alina1380 [7]
3 years ago
13

Y over 4 -3=4 what is y?

Mathematics
2 answers:
quester [9]3 years ago
6 0

Answer:

y = 28

Step-by-step explanation:

As I interpret your post, you want to solve

y

---- - 3 = 4 for y.  

 4

First, add 3 to both sides:  y/4 = 7.

Next, mult. both sides by 4 to eliminate the fraction:  y = 28.

Otrada [13]3 years ago
4 0

Solution, solve\:for\:y,\:\frac{y}{4}-3=4\quad :\quad y=28

Steps:

\frac{y}{4}-3=4

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}, \frac{y}{4}-3+3=4+3

\mathrm{Simplify}, \frac{y}{4}=7

\mathrm{Multiply\:both\:sides\:by\:}4, \frac{4y}{4}=7\cdot \:4

\mathrm{Simplify}, y=28

\mathrm{The\:Correct\:Answer\:is\:y=28}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

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Bezzdna [24]
Here you go 4.32/ 0.50=8.64
3 0
3 years ago
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You roll a standard number cube. Find P(number is not 2).
Morgarella [4.7K]
A standard number cube has 6 sides, and so the numbers are:

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P, is any of those numbers that <em>are not 2</em>.

2 is one of the numbers in 6, and so it is 1/6 of the die.

6/6 - 1/6 = 5/6

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7 0
3 years ago
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Triangle ABC is similar to triangle DEF.
Sav [38]

Answer: x=7.7, y=40

3/x = 15/38.5

38.5*3=115.5

115.5/15= 7.7

x=7.7


3/8 = 15/y

15*8=120

120/3= 40

y=40


orrrr you can just easily find the scale factor which is 5, multiply 8 by 5 and get 40. And 38.5/5 which is 7.7

7 0
2 years ago
Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams
hram777 [196]

Answer:

X(16)=25.71grams

Step-by-step explanation:

let X(t) denote grams of C formed in  t mins.

For X grams of C we have:

\frac{2}{3}Xg of A and \frac{1}{3}Xg of B

Amounts of A,B remaining at any given time is expressed as:

40-\frac{2}{3}Xg of A and  50-\frac{1}{3}Xg  of B

Rate at which C is formed satisfies:

\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt  \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}

Apply the initial condition,X(0)=0 ,to the expression above

0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}

Now at X(8)=15:

15=90-\frac{90}{90\times 8k+1}  \ ->75=\frac{90}{720k+1}\\k=0.0002778

Substitute  in X(t) to get

X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71

5 0
3 years ago
How do I graph this someone plz tell me.
hodyreva [135]
Easy. your starting point is going to be at -2 on the y-axis. then from that point (-2) you're going to go down 1 and then over 2. then draw a straight line through those two points. The line should be a negative line.
7 0
3 years ago
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