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alina1380 [7]
3 years ago
13

Y over 4 -3=4 what is y?

Mathematics
2 answers:
quester [9]3 years ago
6 0

Answer:

y = 28

Step-by-step explanation:

As I interpret your post, you want to solve

y

---- - 3 = 4 for y.  

 4

First, add 3 to both sides:  y/4 = 7.

Next, mult. both sides by 4 to eliminate the fraction:  y = 28.

Otrada [13]3 years ago
4 0

Solution, solve\:for\:y,\:\frac{y}{4}-3=4\quad :\quad y=28

Steps:

\frac{y}{4}-3=4

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}, \frac{y}{4}-3+3=4+3

\mathrm{Simplify}, \frac{y}{4}=7

\mathrm{Multiply\:both\:sides\:by\:}4, \frac{4y}{4}=7\cdot \:4

\mathrm{Simplify}, y=28

\mathrm{The\:Correct\:Answer\:is\:y=28}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

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Step-by-step explanation:

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Probability is a measure of how likely an event is to occur. Match the probabilities below with each statement. 0, 0.01, 0.3, 0.
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Step-by-step explanation:

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8 0
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Read 2 more answers
Is this expression equivalent to 1.5?<br><br> 15.0 / 10<br> 15.0 (divided by) 10
Dmitriy789 [7]

Answer:

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Step-by-step explanation:

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4 0
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Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0
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