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inysia [295]
3 years ago
5

How do you solve 5 + 1 7/8

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
7 0
Turn 5 into 5/1 and 1 7/8 into 15/8. Add them and turn the number back to a proper fraction.  After that your final answer will be 2 4/8.  HOPE THIS HELPS!
Elis [28]3 years ago
5 0
The answer to your problem is 6 7/8.
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check the picture below.


\bf (\stackrel{a}{-20},\stackrel{b}{-21})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{-20}\\ b=\stackrel{opposite}{-21}\\ \end{cases} \\\\\\ c=\sqrt{(-20)^2+(-21)^2}\implies c=\sqrt{841}\implies c=29 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-20}}{\stackrel{hypotenuse}{29}}~\hfill

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