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3241004551 [841]
2 years ago
14

Solve the equation 4(p+5) = 21.

Mathematics
1 answer:
Maslowich2 years ago
5 0

Answer:

p=1/4

Step-by-step explanation:

4(p+5)=21

4p+20=21

4p=1

p=1/4

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lyudmila [28]

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4 0
3 years ago
Please help fast:(((
Airida [17]
At the bottom of the motion: The potential energy of the spring is at a maximum since the spring is stretched at its maximum extension. The potential energy due to gravity is at a minimum, since the mass is lifted the least amount above ground.
3 0
3 years ago
Calculate the slope
lesya692 [45]

Answer:

Undefined

Step-by-step explanation:

Slope us (y2-y1)/(x2-x1)

(9-4)/(3-3)

Cant divide by zero

3 0
3 years ago
Melissa makes and sells necklaces and bracelets. One day she made a total of 28 pieces of jewelry. On this day the number of bra
murzikaleks [220]

Answer:

Number of necklaces = 8

Number of bracelets = 20

Step-by-step explanation:

Given that:

Mellisa is making and selling the necklaces and bracelets.

Number of pieces of jewelry made on one day = 28

Number of bracelets was 4 more than the twice the number of necklaces.

To find:

Number of each type of jewelry made = ?

Solution:

Let number of bracelets = b

Let number of necklaces = n

As per question statement:

b+n=28 ...... (1)

b = 2n+4 ...... (2)

Putting the value of b in equation (1):

2n+4+n=28\\\Rightarrow 3n = 28-4\\\Rightarrow 3n = 24\\\Rightarrow n =\bold{8}

By equation (1):

b + 8 =28\\\Rightarrow b = \bold{20}

So, the answer is:

Number of necklaces = 8

Number of bracelets = 20

7 0
3 years ago
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
Alexxandr [17]

Answer:

P = 0,0012     or   P = 0.12 %

Step-by-step explanation:

We know for normal distribution  that:

μ ± σ  in that range we find 68.3 % of all values

μ ± 2σ      ⇒  95.5 %      and

μ ± 3σ      ⇒  99.7 %  

Fom problem statement

We have to find (approximately)  % of cars that reamain in service between 71 and 83 months

65 + 6 = 71                ( μ + σ )     therefore 95.5 % of values are from 59 and up to 71  then by symmetry   95.5/2  =  49.75 of values will be above mean

Probability between 65 and 71 is  49.75 %

On the other hand 74 is a value for mean plus 1, 5 σ  and

74 is the value limit for mean plus 1,5 σ and correspond  to 49,85 (from z=0 or mean 65).

Then the pobabilty for 83 have to be bigger than 49.85 and smaller than 0,5 assume is 49.87

Finally the probability approximately for cars that remain in service between 71 and 83 months is :  0,4987 - 0.49.75

P = 0,0012     or   P = 0.12 %

8 0
4 years ago
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