What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
Average rate of change means find the slope of the secant line. So if there is a function f(x) and you want to find the average R.O.C over the interval [a,b], it would be (f(b)-f(a))/(b-a)
1. (f(3)-f(1))/(3-1)= (0-(-2))/2= 1, so D.
2. Same concept; (8-4)/(3-1)=2, so A.
3. Again, (39-(-1))/5= 8, B.
Answer:
W=50M
Step-by-step explanation:
Since there are 18 workers per 900 minerals, divide out to simplify.
STARTING EQUATION: 900m=18w
SIMPLIFY: divide both sides by 18.
SIMPLIFIED: 50m=1w
There is your answer!
Answer:
Depth is the downward direction actually and height is upward direction got it?
Step-by-step explanation:
