Use the distributive property to remove the parentheses.

Mathematics

1 answer:

bezimeni [28]4 years ago

7 0

Where are the parentheses? happy to help, but a bit confused by the question

You might be interested in

Which unit should be used to measure the amount of water used

Vesna [10]

Answer:

iters and millimets

Step-by-step explanation:

Ur welcome:)

7 0

3 years ago

Find the midpoint of NP⎯⎯⎯⎯⎯ given N(2a, 2b) and P(2a, 0).

geniusboy [140]

Answer:

(2a, b )

Step-by-step explanation:

Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ $\frac{1}{2}$ (x₁ + x₂ ), $\frac{1}{2}$ (y₁ + y₂ ) ]

Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus

midpoint = [ $\frac{1}{2}$ (2a + 2a), $\frac{1}{2}$ (2b + 0 ) ] = (2a, b )

4 0

3 years ago

Does this graph represent a function? What is the domain and range of the graph

Daniel [21]

Yes it is a function. It passes the vertical line test. In other words, it is impossible to draw a single vertical line through more than one point on the V shaped graph. Any input leads to exactly one output.

The domain is the set of all real numbers. This is because we can plug in any x value leading to some specific y value. There are no holes or gaps or jumps to indicate we must restrict any given x value. The domain would not be the set of whole numbers only because values between the whole numbers (eg: decimal values like x = 2.75) work just fine.

The range is the set of y values such that y is either 0 or larger than 0. In short, the range is $y \ge 0$ . Notice how any point on the V shaped graph has a y coordinate that is either 0 or larger than 0. It is impossible to get a y value that is negative.

--------------------------------------------------------------------

In summary,
Yes it is a function
Domain: all real numbers
Range: $y \ge 0$
So the answer is choice B

6 0

3 years ago

Find an equation of the circle that has center (-4,3) and passes through (6,-4).

kumpel [21]

Answer:

$(x+4)^2+(y-3)^2=149$

Step-by-step explanation:

The equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center of the circle and $r$ is the radius of the circle.

Given that $(h,k)\rightarrow(-4,3)$ and it passes $(6,-4)$ , their distance between each other must the radius of the circle, so we can use the distance formula to find the radius: