True or false? It is possible to circumscribe a circle about the quadrilateral below
2 answers:
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Answer:
a) (-5,0) and (1,0)
b) (0,-5)
c) minimum
See attached graph.
Step-by-step explanation:
To graph the function, find the vertex of the function find (-b/2a, f(-b/2a)). Substitute b = 4 and a = 1.
-4/2(1) = -4/2 = -2
f(-2) = (-2)^2 + 4(-2) - 5 = 4 - 8 - 5 = -4 - 5 = -9
Plot the point (-2,-9). Then two points two points on either side like x = -1 and x = -3. Substitute x = -1 and x = -3
f(-1) = (-1)^2 + 4 (-1) - 5 = 1 - 4 - 5 = -8
Plot the point (-1,-8).
f(-3) = (-3)^2 + 4(-3) - 5 = 9 - 12 - 5 = -8
Plot the point (-3,-8).
See the attached graph.
The features of the graph are:
a) (-5,0) and (1,0)
b) (0,-5)
c) minimum
That probability is about 6.7%.
