The area of the square is 9 in^2
The side of a square is the square root of the area.
Side of square = √9 = 3 inches.
The side of the square is the diameter of the inscribed circle.
Circumference of a circle is PI x diameter.
Circumference of inscribed circle = 3.14 x 3 = 9.42 inches
The diameter for the circumscribed circle would be the diagonal of the square which is 3√2 = ( Side length x √2) ≈ 4.2426
The circumference = 3.14 x 3√2 = 13.321
Find the ratio between the two circles:
Circumscribed / inscribed =
13.321 / 9.42 = 1.41
Answer:Yes
Step-by-step explanation:
It is a function if no values of x repeat
Let's assume
number of seats in each row =x
we are given
The number of seats in each row exceeds the number of rows by 20
number of seats = number of rows +20
x = number of rows +20
so, number of rows =x-20
total number of seats = (number of seats in each row)*(number of rows)
so, we can plug values
and we get
now, we can solve for x
since, number of seats can not be negative
so, number of seats in each row is 63.....................Answer
Since segment AC bisects (aka cuts in half) angle A, this means the two angles CAB and CAD are the same measure. I'll refer to this later as "fact 1".
Triangles ABC and ADC have the shared segment AC between them. By the reflexive property AC = AC. Any segment is equal in length to itself. I'll call this "fact 2" later on.
Similar to fact 1, we have angle ACB = angle ACD. This is because AC bisects angle BCD into two smaller equal halves. I'll call this fact 3
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To summarize so far, we have these three facts
- angle CAB = angle CAD
- AC = AC
- angle ACB = angle ACD
in this exact order, we can use the ASA (angle side angle) congruence property to prove the two triangles are congruent. Facts 1 and 3 refer to the "A" parts of "ASA", while fact 2 refers to the "S" of "ASA". The order matters. Notice how the side is between the angles in question.
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Once we prove the triangles are congruent, we use CPCTC (corresponding parts of congruent triangles are congruent) to conclude that AB = AD and BC = BD. These pair of sides correspond, so they must be congruent in order for the entire triangles to be congruent overall.
It's like saying you had 2 identical houses, so the front doors must be the same. The houses are the triangles (the larger structure) and the door is an analogy to the sides (which are pieces of the larger structure).