Answer:
Step-by-step explanation:
4+9+14+...+494
d=9-4=5
\[a_{n}=a_{1}+(n-1)d\]
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2 answers:
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Answer:
Step-by-step explanation:
<u><em>Let's check it using Pythagorean Theorem:</em></u>
Where c is the longest sides, a and b are rest of the 2 sides
1) 9 , 40 , 46
=>
=>
=> 2116 = 81 + 1600
=> 2116 ≠ 1681
So, this is not a Pythagorean Triplet
2) 16, 30 and 34
=>
=>
=> 1156 = 256 + 900
=> 1156 = 1156
No need to check more as we've found the one which is not a Pythagorean Triplet.
Answer:
Given the statement: The quotient of a number x and 4 is atmost 5.
Let x be a number.
"quotient of a number x and 4" represented as
"at most" means ''
Therefore, the inequality for the given statement is;
Solve the above inequality:
multiply both sides by 4 we get;
Simplify:
Therefore, the solutions for the given inequality is: