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Karo-lina-s [1.5K]
3 years ago
9

What is the slope of the line that passes through the points (-2, 4) and (10,-5)?

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

Answer:

-12/9

Step-by-step explanation:

You might be interested in
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
The expression 3(x-9) is equivalent to
Inessa05 [86]
The answer to this question would be D. 3(x)-3(9)
8 0
3 years ago
What is 500 x 50, 000
kogti [31]
Answer is 25,000,000
6 0
3 years ago
Do all straight lines that are functions have inverses?
tino4ka555 [31]

Answer: Not all Functions have a inverse

Happy To Help :)

Step-by-step explanation:

7 0
2 years ago
I know its easy but i suck at math pls help
e-lub [12.9K]

Answer:

-6.8125

Step-by-step explanation:

Convert 13/16 to a decimal.

Write -6 down

You get -6.8125.

Hope this helps! If it does, please mark me brainliest, and press thank you to help me. Thank you! ;)

Good luck on whatever you are doing.

3 0
4 years ago
Read 2 more answers
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