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kipiarov [429]
2 years ago
11

The area of the base b is the area of a square with sides of length 230 m. so, v =

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
4 0
Not completely sure what you are asking, but the area of a square with the side lengths of 230m would be 230*230=52,900.
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A(2,3)b(7,3),and c(7,-2) are three verticed of square abcd. what are the coordinated of vertex d​
sladkih [1.3K]

Answer:

D (2,-2)

Step-by-step explanation:

  • The coordinates are the pair (x,y) in the axis.
  • We already have three vertexs: a: (x,y)=(2,3); b:(x,y)= (7,3) and c: (x,y)=(7,-2).
  • If you see the picture attached, where all points available are in pink, you will see that the distance between the sides that are already defined equals 5.
  • Because all squares have equals sides, then we must find the missing side that will be at a distance of 5 between the other two vertexs.
  • That point is d (x,y)=(2,-2).

3 0
2 years ago
$22 haircut, 15% tip
expeople1 [14]

Answer:

3,3$

Step-by-step explanation:

( 22 / 100 ) x 15 :)

8 0
3 years ago
Read 2 more answers
Find the value of x in the figure
Archy [21]

Answer:

x = 35

Step-by-step explanation:

The sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

Here n = 6, thus

sum = 180° × 4 = 720°

Sum the given angles and equate to 720

4x - 5 + 117 + 3x - 3 + 3x + 6 + 118 + 4x - 3 = 720, that is

14x + 230 = 720 ( subtract 230 from both sides )

14x = 490 ( divide both sides by 14 )

x = 35

7 0
2 years ago
Find the angular size of a circular object with a 3​-inch diameter viewed from a distance of 6 yards.
Rom4ik [11]
Check picture below
thus \bf tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\qquad thus
\\\\\\
tan(\theta)=\cfrac{3}{6}\implies tan(\theta)=\cfrac{1}{2}
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\theta=tan^{-1}\left( \cfrac{1}{2} \right)

8 0
2 years ago
Suppose the cost of producing tires, t, is defined by C(t) = -0.45+2 + 12+ 450. Determine
loris [4]

Answer:

Option (A)

Step-by-step explanation:

Function to represent the cost of producing 't' tires is,

C(t) = -0.45t² + 12t + 450

Since average rate of change of the function in the interval (a, b) is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

Following this rule,

Average rate of change in the interval (2, 4)

= \frac{C(4)-C(2)}{4-2}

= \frac{490.8-472.2}{4-2}

= 9.3

Average rate of change in the interval (46, 48)

= \frac{-10.8-49.8}{2}

= -30.3

Average rate of change in the interval (12, 14)

= \frac{529.8-529.2}{2}

= 0.3

Average rate of change in the interval (22, 24)

= \frac{478.8-496.2}{24-22}

= --8.7

Average rate of change is greatest in the interval (2, 4)

Option (A) will be the answer.

6 0
2 years ago
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