What are the critical points for the inequality x^2-4/x^2-5x+6 < 0? D is the correct Answer!

Mathematics

2 answers:

erastovalidia [21]3 years ago

5 0

Could you kindly be more specific in your question? It would make it a lot easier to answer. Thanks!

mojhsa [17]3 years ago

3 0

The critical points of a function are the values of x, for which the function is equal to zero.
Given the inequality

A rational function is said to be equal to zero when the numerator is equal to zero.
Thus

Therefore, the critical point of the inequality is x = -2 and x = 2.

You might be interested in

what is the point-slope form of the equation of the line passing through the points (–6, –4) and (2, –5).

ioda

Answer:

The equation of the line would be y + 4 = -1/8(x + 6)

Step-by-step explanation:

To find the point-slope form of the line, start by finding the slope. You can do this using the slope formula below along with the two points.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-4 - -5)/(-6 - 2)

m = 1/-8

m = -1/8

Now that we have the slope, we can use that along with one of the points in the base form of point-slope.

y - y1 = m(x - x1)

y + 4 = -1/8(x + 6)

7 0

3 years ago

Help plz what is 7-6v=-5-8v

kirill115 [55]

v=-6 is the right answer. First you had to subtract by 7 from both sides of equation, and it gave us, $7-6v-7=-5-8v-7$ . And then simplify, and it gave us, $-6v=-8v-12$ . You can also add by 8v from both sides of equation, and it gave us, $-6v+8v=-8v-12+8v$ . Next simplify, and it gave us, $2v=-12$ . Then you divide by 2 from both sides of equation, and it gave us, $\frac{2v}{2}=\frac{-12}{2}$ . And finally simplify, and it gave us the answer is v=-6 is the right answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie