Answer:
3.10 i think i saw in quiz i hope you do a great job and ace the test
Step-by-step explanation:
2(5m+4)=2(3m-10)
10m+8= 6m-20
-6m -6m
4m+8= -20
-8 -8
4m= -28
m = -7
1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer:
If you mean 4x-x=(x+4), x= 2
Step-by-step explanation:
Answer:7.967
Step-by-step explanation:
