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yarga [219]
4 years ago
14

Find the missing numbers in the ratio table Undo - Redo 1 6 10 5 20

Mathematics
1 answer:
mojhsa [17]4 years ago
7 0

Answer:

difficult bro answer is 18

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Helppppppppppppp i need this homework done by today
lbvjy [14]

Answer: 13. -68

14. 36

15. -36

16. -3

17. 10

18. -4

19. 1310 ft

20. 330 ft

Step-by-step explanation:

13. 34*(-2)=-68

14. -9*(-4)=

-(9*(-4))=

-(-36)=36

15. 12*(-3)=-36

16. -12/4=-3

17. -20/(-2)=

20/2=10

18. 200/(-50)=-4

19. -1640*(-1)-(-330*(-1))=

1640-(-330*(-1))=

1640-330=1310 ft

20. -990*(-1)-(-660*(-1))=

990-(-660*(-1))=

990-660=330 ft

7 0
1 year ago
If 60% of a KNOWN NUMBER is 180, what is the 40% of that UNKNOWN NUMBER?
Lana71 [14]

Step-by-step explanation:

I think you mean you want to find out 40% of a number,, when 60% of it is 180, so I'll answer that:

60% = 180

÷6

10% = 30

x4

40% = 120

(if you want to find 100%, multiply 30 by 10)

Hopefully this helps :)

4 0
2 years ago
Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
Which graph represents (x - 1)2/9 (y-3)2/1
Marat540 [252]
We can only see one graph here
7 0
3 years ago
Read 2 more answers
Emily buys 14 balloons. 3 are red, 4 are white, and the rest are blue. What is the ratio of blue balloons to the total number of
8_murik_8 [283]

Answer:

3:4:7

Step-by-step explanation:

14-(3+4)

=14-7

=7

red:white:blue

3:4:7

5 0
3 years ago
Read 2 more answers
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