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3 years ago

I need urgent help.

Mathematics

1 answer:

NeX [460]3 years ago

4 0

Answer:

x y

2 76

4 64

7 47

9 34

13 10

Step-by-step explanation:

If we have an initial value of 88, that would be the y intercept

The rate of change -6 which is the slope

y = -6x+88

Let x =2

y = -6(2) +88 =

-12+88

= 76

Let y = 64

64 = -6x +88

Subtract 88 from each side

64-88 = -6x

-24= -6x

Divide by -6

-24/-6 =x x=4

Let y = 46

46 = -6x +88

Subtract 88 from each side

46-88 = -6x

-42= -6x

Divide by -6

-42/-6 =x x=7

Let x =9

y = -6(9) +88 =

-54+88

= 34

Let y = 10

10 = -6x +88

Subtract 88 from each side

10-88 = -6x

-78= -6x

Divide by -6

-78/-6 =x x=13

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Answer:

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Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that $X \sim Poisson(\lambda=4)$

The probability mass function for the random variable is given by:

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And f(x)=0 for other case.

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$P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)$

Using the pmf we can find the individual probabilities like this:

$P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183$

$P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733$

$P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465$

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$P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692$

b. Compute P(4≤X≤ 8).

$P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595$

$P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298$

$P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452$

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$P(X \geq 8) = 1-P(X$

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$P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)$

$P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954$

$P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563$

$P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042$

$P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559$

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I need urgent help. ​

I need urgent help.