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suter [353]
3 years ago
8

A.15 B.12 C.10 D.7 E.4 F.2

Mathematics
1 answer:
Fofino [41]3 years ago
6 0

The triangle inequality requires that the sum of the shorter sides, a, b of a triangle be greater than the third side c.


This means that

a+b > c


If the third side is the longest, then a=6, b=9, and c<15

That makes 15 an impossible side.


If the third side x is less than 9, then

6+x<9, that makes

x<9-6=3.

That makes 2 an impossible side.


So the possible sides are 4,7,10,12,

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Answer:

33 cents

Step-by-step explanation:

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3 years ago
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Which of the following is not a possible cross section of a cylinder
SVEN [57.7K]

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Square

Step-by-step explanation:

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How to solve this equation 5x-4-7x=4
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Answer:

x= -4

Step-by-step explanation:

Simplifying

5x + -4 = 7x + 4

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-4 + 5x = 4 + 7x

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.

-4 + 5x + -7x = 4 + 7x + -7x

Combine like terms: 5x + -7x = -2x

-4 + -2x = 4 + 7x + -7x

Combine like terms: 7x + -7x = 0

-4 + -2x = 4 + 0

-4 + -2x = 4

Add '4' to each side of the equation.

-4 + 4 + -2x = 4 + 4

Combine like terms: -4 + 4 = 0

0 + -2x = 4 + 4

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Combine like terms: 4 + 4 = 8

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Divide each side by '-2'.

x = -4

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3 0
3 years ago
The general equation of the plane that contains the points (1, 0, 2), (−1, 1, −2), and the origin is of the form ax + by + cz =
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Answer:

2x-z=0 is the equation of the plane.

Step-by-step explanation:

Given that the plane passes through the points (1,0,2) and (-1,1,-2)

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Any plane passing through 3 given points is given as

\left[\begin{array}{ccc}x-x_1&y-y_1&z-z_1\\x_2-x_1&y_2-y_1&z_2-z_1\\x_3-x_1&y_3-y_1&z_3-z_1\end{array}\right] =0

Substitute the three points to get

\left[\begin{array}{ccc}x-1&y&z-2\\-1-1&1&-2-2\\0-1&0&0-2\end{array}\right] \\=0\\(x-1)(-2) -y(4-4)+(z-2)(1) =0\\-2x+z=0\\2x-z-=0

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