B is correct the devotion is only 2 compared to 4.
A is wrong because variate A has higher trees then variate B
C is wrong because deviation for A is 4 compared to 2 ( opposite of B)
D is wrong because 4th one is 10 for A and 13 for B. 10 is not greater than 13
Answer:
•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25
•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25
cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗
sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5
For ABC:
The interior angle of C is 180 - 142 = 38
The three interior angles add up to 180°
(2x - 15) + (x - 5) + 38 = 180
3x - 20 + 38 = 180
3x + 18 = 180
3x = 162
x = 54
The measure of angle ABC = x - 5 = 54 - 5 = 49
For JKL:
The interior angle of L is 180 - 100 = 80°
The 3 interior angles add up to 180°
(2x + 27) + (2x - 11) + 80 = 180
4x + 16 + 80 = 180
4x + 96 = 180
4x = 84
x = 21
The measure of angle JKL is 2x - 11 = 2(21) - 11 = 42 - 11 = 31°
80,000,000 + 9,000,000 + 100,00 + 70,000 +300 + 20 + 6
Answer: kindly check explanation
Step-by-step explanation:
Given the following :
Total area of parknand path way = 74,464 m2.
Dimension of park = 350m by 200m
Using the area of rectangle formula:
Area = Length * width
Area of park = 350m * 200m
Area of park = 70,000
Area of path = (74,464 - 70,000) = 4,464m2
Since path has uniform width, then width of the the path is sqrt(4464) = 66.8m
2.) the path of the park seems a bit narrow, hence, I wouldn't love children to bike and jog in such a narrow path
