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Alenkasestr [34]
3 years ago
11

A five-sided solid has the numbers 1, 2, 3, 4, and 5. What is the probability of rolling two five-sided number solids and gettin

g a sum of either a 4 or an 8?
Mathematics
1 answer:
Klio2033 [76]3 years ago
7 0
We assume the probability on each side is equally probable with probability 1/5.
sum=4 has outcomes:{1,4; 2,3; 3,2; 4,1}  4 possible outcomes
sum=8 has outcomes:{3,5; 4,4; 5,3} 3 possible outcomes.
Total possible outcomes = 5*5=25
there probability of rolling a sum of 4 or 8, by the law of addition, equals
4/25+3/25=7/25

Note: a regular (i.e. fully symmetric) five-sided solid does not exist, so there has to be asymmetry among the probabilities of the five possible outcomes.  In addition, it does not have a "top" face, so that makes rolling a five-sided solid a little more difficult to visualize.
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Eduardwww [97]

Answer:

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Step-by-step explanation:

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expand further:

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take y to be 3, then substitute:

( {x}^{3}  - 3^3) =  {(x - 3)}^{3}  - 9x(3 - x)

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3 years ago
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