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1 year ago

Find the domain and range for the function shown in the graph given below.

Mathematics

1 answer:

eimsori [14]1 year ago

7 0

Answer:

Domain: [-20, 20]

Range: [-30, 5]

Step-by-step explanation:

The domain is the set of x values and the range is the set of y values.

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Which of the following would best be solved using factoring the difference of squares? 2² + 3x - 10 = 0 O 3r² + 12x = 8 2³ +52²

IgorC [24]

Given: Different equations

To Determine: Which would be best solved using difference of two squares

Solution

The factorization of a difference of two squares is given below

$a^2-b^2=(a-b)(a+b)$

Let us examine each of the given equation

$\begin{gathered} x^2+3x-10=0 \\ x^2-2x+5x-10=0 \\ x(x-2)+5(x-2)=0 \\ (x-2)(x+5)=0 \end{gathered}$ $\begin{gathered} 3x^2+12x=8 \\ 3x^2+12x-8=0 \end{gathered}$ $\begin{gathered} x^3+5x^2-9x-45=0 \\ x^2(x+5)-9(x+5)=0 \\ (x+5)(x^2-9)=0 \\ x^2-9=x^2-3^2=(x+3)(x-3) \\ Therefore \\ (x+5)(x+3)(x-3)=0 \end{gathered}$ $\begin{gathered} x^2-25=0 \\ x^2-5^2=0 \\ (x+5)(x-5)=0 \end{gathered}$

From the above,

$\begin{gathered} x^3+5x^2-9x-45=0 \\ AND \\ x^2-25=0 \end{gathered}$

The two equation above can be solved by difference of two square, but the equation below is the easiest solved using differnce of two square

x² - 25 = 0

3 0

1 year ago

A line with a negative slope intersects a horizontal line 3 units above the x-axis. Select each point that can not be the inters

AnnyKZ [126]

Step-by-step explanation:

Since both lines intersect each other 3 units above the x-axis, the y-value of the point of intersection must be 3.

Looking at the options, (-3, 5), (3, -2) and (0, -3) are all invalid points.

6 0

3 years ago

Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund

lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

$\sigma=\sqrt{\frac{p*(1-p)}{n} }$

If n=1139 and p =0.96, the standard deviation is:

$\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836$

The minimum and maximum usual values are:

$\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n$

$\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62$

5 0

3 years ago

Marking as brainliest

fredd [130]

Answer:

13.1 (3sf)

Step-by-step explanation:

14 ^2 - 5^2 = 171

root 171 = 13.1 (3sf)

5 0

3 years ago

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Sindrei [870]

Answer:

The current intervals for the bins are too wide. Looking at the histogram, it is difficult to draw useful conclusions about the fuel efficiency of the trucks or to see the shape of the data distribution.

Step-by-step explanation:

Here is the Plato answer

6 0

3 years ago

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