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3 years ago

What is one third of 1080

Mathematics

2 answers:

svlad2 [7]3 years ago

7 0

1080 / 3 = 360 x 1 = 360
Happy to Help!

katen-ka-za [31]3 years ago

4 0

I am almost positive that it is 360

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It costs $3.60 to buy one lb of candy. How much would it cost to purchase 5 lbs of candy?

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3 years ago

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What is the area of the polygon below in square units? 4 cm 12 cm 18 cm

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2 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

Equation Solving

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

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2 years ago

Using the circle below find the arc length of RPT. round to the nearest hundredth. use pie. NO SPAMS. THANK YOU!!!!!

Masteriza [31]

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3 years ago

If 3a + 2b = 7 and 2a + 2b = 9 , what is the value of

Simora [160]

Hey there :)

We have two equations:
3a + 2b = 7
2a + 2b = 9

We need to solve simultaneously to find the values of a and b

eq.1 3a + 2b = 7
eq.2 ( 2a + 2b = 9 ) x -1 ) multiply by -1 to cancel 2b

3a + 2b = 7
- 2a - 2b = -9 ( Add both together )
-------------------
a = - 2

Substitute the value you found for a in a in order to find b

3( - 2 ) + 2b = 7 2( - 2 ) + 2b = 9
- 6 + 2b = 7 OR - 4 + 2b = 9
2b = 13 2b = 13
b = $\frac{13}{2}$ b = $\frac{13}{2}$

3 0

3 years ago