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3 years ago

15

Is each line parallel, perpendicular, or neither parallel nor perpendicular to a line whose slope is -3/4?

2 answers:

taurus [48]3 years ago

8 0

You need to draw out the slope on a piece of graph paper and u can figure it out

brilliants [131]3 years ago

4 0

In order for a line to be parallel it must have the same slope of -3/4
in order for a line to be perpendicular it must have the inverse of the slope which would be 4/3
if it is neither of the cases listed above it is neither parallel nor perpendicular

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Also this pls pls pls

Dahasolnce [82]

Answer:

-2 : -1

-1 : -1/2

0 : 0

1 : 1/2

2 : 1

3 : 3/2

4 : 2

5 : 5/2

6 : 3

Step-by-step explanation:

Plug in whatever is on the left side of the table to the x in the equation (1/2 x)

Ex. y = 1/2 (4)

y = 2

4 0

3 years ago

Five cats each ate 1/3 cup of canned food and 1/3 cup of dry food.

Butoxors [25]

Answer:

Step-by-step explanation:

5/ 1/3=1.6x2=3.2

8 0

3 years ago

Read 2 more answers

Which ordered pairs are solutions to the inequality y−2x≤−3?

My name is Ann [436]

we will proceed to resolve each case to determine the solution

we have

$y-2x \leq -3$

$y\leq2x-3$

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

<u>case a)</u> $(5,-3)$

Substitute the value of x and y in the inequality

$-3\leq2*5-3$

$-3\leq7$ -------> is true

so

The ordered pair $(5,-3)$ is a solution

<u>case b)</u> $(0,-2)$

Substitute the value of x and y in the inequality

$-2\leq2*0-3$

$-2\leq-3$ -------> is False

so

The ordered pair $(0,-2)$ is not a solution

<u>case c)</u> $(-6,-3)$

Substitute the value of x and y in the inequality

$-3\leq2*-6-3$

$-3\leq-15$ -------> is False

so

The ordered pair $(-6,-3)$ is not a solution

<u>case d)</u> $(1,-1)$

Substitute the value of x and y in the inequality

$-1\leq2*1-3$

$-1\leq-1$ -------> is True

so

The ordered pair $(1,-1)$ is a solution

<u>case e)</u> $(7,12)$

Substitute the value of x and y in the inequality

$12\leq2*7-3$

$12\leq11$ -------> is False

so

The ordered pair $(7,12)$ is not a solution

Verify

using a graphing tool

see the attached figure

the solution is the shaded area below the line

The points A and D lies on the shaded area, therefore the ordered pairs A and D are solution of the inequality

6 0

3 years ago

Read 2 more answers

The polynomial given below has _____ root(s).2x2 + 5x + 2

Nastasia [14]

2x^2 + 5x + 2 = 0
(x + 2)(2x + 1) = 0
x = -2 x = - 1/2
Letter C

8 0

3 years ago

PLEASE HELP ME I NEED THIS RIGHT NOW

pav-90 [236]

Answer:

The answer is the second one

(-4, 0)

6 0

3 years ago

Read 2 more answers