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lana66690 [7]
3 years ago
14

2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2-2

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0

Answer:

-50

Step-by-step explanation:

VLD [36.1K]3 years ago
5 0

Step-by-step explanation:

Answer is in the attached picture

happy to help.......!!!!

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cupoosta [38]

Answer: C) (-∞,∞)

The domain of the funtion is (-∞,∞)

3 0
2 years ago
7/9% of 1 is equal to what fraction of the quantity
swat32
7/9% is not 7/9 of 1, it's 7/9 of 0.01.

So, it is 0.0078

Hope this helps!
6 0
3 years ago
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts
kirill115 [55]

Answer:

z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666    

p_v =2*P(Z  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=4.5 represent the sample mean

\sigma=1.1 represent the population standard deviation

n=860 sample size  

\mu_o =4.6 represent the value that we want to test

\alpha=0.02 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal or not to 4.6, the system of hypothesis would be:  

Null hypothesis:\mu = 4.6  

Alternative hypothesis:\mu \neq 4.6  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666  

P-value

Since is a two sided test the p value would be:  

p_v =2*P(Z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.02 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.  

5 0
3 years ago
A bag has 6 number tiles numbered one through six. You draw a number tile, replace the tile and draw a second tile. What is the
Ksivusya [100]
Answer:A
explanation : 1/6 x 1/6=1/36=.028 OR 2.8%
3 0
3 years ago
Read 2 more answers
–3x – 3y &gt; –18. <br> –x &lt; –y
Veseljchak [2.6K]

Answer:

hmmm.... -2y/3

hope i helped. :)

6 0
3 years ago
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