In Triangle
ABC with the right angle at C, let a,b, and c be the opposite, the adjacent, and the hypotenuse of ∠A. Then, we have
sin A=ac⇒m∠A=sin−1(ac)
sin B=bc⇒m∠B=sin−1(bc)
I know its not the answer but I hope it was helpful
Given:
The expression is:
To find:
The integration of the given expression.
Solution:
We need to find the integration of .
Let us consider,
![[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ccos%202x%3D2%5Ccos%5E2x%2C1-%5Ccos%202x%3D2%5Csin%5E2x%5D)
![\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Ctan%20%5Ctheta%20%3D%5Cdfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D%5Cright%5D)
It can be written as:
![[\because 1+\tan^2 \theta =\sec^2 \theta]](https://tex.z-dn.net/?f=%5B%5Cbecause%201%2B%5Ctan%5E2%20%5Ctheta%20%3D%5Csec%5E2%20%5Ctheta%5D)
Therefore, the integration of is .
Answer:
i think D is your answer but i could be wrong
The mean is calculated by adding up all of the data points and then dividing the sum by the amount of points added.
The mean fitness score was 3.2 points. If all of the students scored the same thing (3.2 points) then this would be the fitness score of each student.
Thus, the answer is D. 3.2 points.
