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umka21 [38]
3 years ago
13

Diego has $11 and begins saving $5 each week toward buying a new phone. At the same time that Diego begins saving, Lin has $60 a

nd begins spending $2 per week on supplies for her art class.
Is there a week when they have the same amount of money? How much do they have at that time?
Mathematics
1 answer:
Nata [24]3 years ago
6 0

Answer:

Let x represents the week and y represents the amount of money.

As per the given statement:

Diego has $11 and begins $5 each week toward buying a new phone.

⇒               ......[1]

It is also given that Lin $60 and begins spending $2 per week.

⇒               ....[2]

when they have the same amount.

equate [1] and [2] we get;

Add both sides 2x we get;

Subtract 11 from both sides we get;

Divide both sides by 7 we get;

x = 7

Substitute the value of x = 7 in [1] we have;

Therefore, at x= 7 week they have the same amount of money and they  have the amount at that time, $ 46

Step-by-step explanation:

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Using traditional methods, it takes 10.1 hours to receive a basic driving license. A new license training method using Computer
Law Incorporation [45]

Answer:

We need to conduct a hypothesis in order to check if the technique performs differently than the traditional method, the system of hypothesis would be:  

Null hypothesis:\mu =10.1  

Alternative hypothesis:\mu \neq 10.1

t=\frac{10.5-10.1}{\frac{1.4}{\sqrt{12}}}=0.990    

p_v =2*P(t_{(11)}>0.990)=0.343    

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL  reject the null hypothesis, so we can't conclude that the technique performs differently than the traditional method at 10% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=10.5 represent the sample mean

s=1.4 represent the sample standard deviation

n=12 sample size  

\mu_o =10.1 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the technique performs differently than the traditional method, the system of hypothesis would be:  

Null hypothesis:\mu =10.1  

Alternative hypothesis:\mu \neq 10.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{10.5-10.1}{\frac{1.4}{\sqrt{12}}}=0.990    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=12-1=11  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(11)}>0.990)=0.343  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL  reject the null hypothesis, so we can't conclude that the technique performs differently than the traditional method at 10% of signficance.  

7 0
3 years ago
Evaluate the expression when a= 2 and c=-4.<br> -a +5c
-Dominant- [34]
The answer would be 18
4 0
3 years ago
A flow meter is attached in a hydraulic line that measures 18 gal/min. The line has an inside diameter of 1.0 in. What is the fl
snow_tiger [21]

The flow velocity measured as in/min at the meter is 5924.13 in/min

<h3 /><h3>Volumetric flow rate</h3>

We know that the volume flow rate Q = Av where

  • A = cross-sectional area of pipe and
  • v = flow velocity

Now, Q = 18 gal/min

Converting this to in³/min, we have

Q = 18 gal/min = 18 × 1 gal/min = 18 × 231 in³/min = 4158 in³/min

A = πd²/4 where d = diameter of pipe = 1.0 in.

<h3 /><h3>Flow velocity, v</h3>

Since Q = Av, making v subject of the formula, we have

v = Q/A

v = 4Q/πd²

Substituting the values of the variables into the equation, we have

v = 4Q/πd²

v = 4 × 4158 in³/min ÷ π × (1.0 in)²

v = 16632 in/min ÷ π

v = 5924.13 in/min

So, the flow velocity measured as in/min at the meter is 5924.13 in/min

Learn more about flow velocity here:

brainly.com/question/15648466

5 0
2 years ago
110 as a product of prime numbers
sweet [91]
110 = 11 \times 10

110 = 11 \times \ 5 \times 2

So it is the product of 5 \times 2 \times 11

And 2,5 and 11 are prime numbers, so there you go :)
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There are 135 people and three door prizes. how many ways can door prizes of $7,500, $750 and $75 be distributed?
igomit [66]

Answer: 2405970 ways

Step-by-step explanation:

When the order of selecting r individuals out of n individual , we use permutations.

The number of permutations of r things taking out of n things is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Given : There are 135 people and three door prizes .

i.e. n= 135 , r= 3

Then, the total number of ways = ^{135}P_3=\dfrac{135!}{(135-3)!}

=\dfrac{135\times134\times133\times132!}{132!}\\\\=135\times134\times133\\\\=2405970

Hence, there are 2405970 ways to distribute door prizes of $7,500, $750 and $75 .

6 0
4 years ago
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