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babunello [35]
3 years ago
13

Among all the rectangles whose perimeters are 100 feet, find the dimensions of the one with the maximum area. explain step by st

ep.
Mathematics
1 answer:
kompoz [17]3 years ago
7 0
<span>We let x be the length and y be the width of the rectangle. Then,
 
Perimeter = 2x + 2y
100 = 2x + 2y
50 = x + y
y = 50 - x
 
Area = xy
A = x(50 - x)
A = 50x - x^2
 
We then take the derivative; set it equal to zero:
 
A ' = 50 - 2x
0 = 50 - 2x
2x = 50
x = 25
y = 50 - x
y = 50 - 25
y = 25
 
Therefore, the dimensions are 25 and 25.</span>
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Suppose that you toss a fair six-sided {1,2,3,4,5,6} die and let X represent the outcome obtained. Find the expected volume of a
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Answer:

The expected volume of the box is 364 cubic inches.

Step-by-step explanation:

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  • (When X = 3) Y = 3²*24 = 216, with probability 1/6 (the same than P(X=3)
  • (When X = 4) Y = 4²*24 = 384, with probability 1/6 (the same than P(X=4)
  • (When X = 5) Y = 5²*24 = 600, with probability 1/6 (the same than P(X=5)
  • (When X = 6) Y = 6²*24 = 864, with probability 1/6 (the same than P(X=6)

As a consequence, the expected volume of the box in cubic inches is

E(Y) = 1/6 * 24 + 1/6*96 + 1/6*216+ 1/6*384+ 1/6*600+1/6*864 = 364

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Step-by-step explanation:

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