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Semenov [28]
3 years ago
9

Please Help, Thank you so much.

Mathematics
1 answer:
NeX [460]3 years ago
8 0

(-2x^3 +x -5) and (x^3 -3x-4)

(a) To find product we multiply both expressions

First distribute -2x^3 inside the second parenthesis (x^3 -3x-4)

-2x^6 + 6x^4 +8x^3

next  distribute x inside the second parenthesis (x^3 -3x-4)

(x^4 -3x^2-4x)

Next distribute -5 inside the second parenthesis (x^3 -3x-4)

(-5x^3 + 15x + 20)[

Finally we add all the product terms we got

-2x^6 + 6x^4 +8x^3 + x^4 -3x^2-4x + -5x^3 + 15x + 20

Combine like terms

-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11 x + 20

(b) yes they are same

Because interchanging of expression does not affect the product

For example 5 * 2 = 2*5 they are same.

So both the product are equal


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Help with this math problem
marishachu [46]

see explanations

Step-by-step explanation:

Formula for mid-point is;

midpoint=((x_1+x_2)/2,(y_1+y_2)/2)

1.Given S(-3,4), U(-3,0) and T(5,0) then finding the mid-points

SU = [(-3+-3)/2,(4+0)/2] =(-3,2)

TU= [(-3+5)/2,(0+0)/2] =(1,0)

ST=[(-3+5)/2,(4+0)/2]=(1,2)

2.Mid-point formula for this case given W(-5,1) and Z(3,3) will be;

Midpoint = [ (x₁+x₂)/2,(y₁+y₂)/2]

Midpoint= [(-5+3)/2 ,(1+3)/2]

Midpoint=(1,2)

3. Finding the length of segments and the midpoint of the segments

Formula for length of segment, d, is given as;

For C(-1,5) and D(5,1)

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2} \\\\d=\sqrt{(1-5)^2+(5--1)^2} =\sqrt{-4^2+6^2} =\sqrt{16+36} =\sqrt{52} =7.21

Midpoint of the segment CD will be

[(-1+5)/2,(5+1)/2] = (2,3)

For E (-3,-6) and F(5,0)

d=\sqrt{(0--6)^2+(5--3)^2} =\sqrt{6^2+8^2} =\sqrt{36+64} =\sqrt{100} =10

The midpoint for segment EF will be;

[(-3+5)/2 ,(-6+0)/2] =(1,-3)

For L(-4,4) and M(-1,-5)

d=\sqrt{(-5--4)^2+(-1-4)^2} \\d=\sqrt{-1^2+-5^2} \\\\d=\sqrt{1+25}=\sqrt{26} =5.1

Learn More

Midpoint of a segment :brainly.com/question/10424143

Distance of a segment :brainly.com/question/11591660

Keywords :midpoint, midpoint formula, segment length, line segment

#LearnwithBrainly

4 0
4 years ago
How do you complete problem number 4?
brilliants [131]
(I'm going to translate y' to dy/dx as it makes it easier to read for me, you could change it back if you wanted.)
x \frac{dy}{dx} -y=0
\frac{dy}{dx} = \frac{y}{x}
\int \frac{1}{y} dy= \int \frac{1}{x} dx (separate the variables)
\ln y=\ln x +c
\ln y = \ln kx (by letting c = ln k and using log laws)
y=kx (raise everything to power e)
3=k\times1 \implies k=3    (applying boundary conditions)
Particular solution: y=3x
3 0
3 years ago
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