represents the set that contains all the elements that are in at least one of the sets, so 
.
We want the complement of this set (in other words, the set with all the elements in the universal set but not in the given set).
This set is {3, 4, 11, 13, 14, 15, 17, 24}
<EFD is also shown as e on the diagram. It is 90 degrees. <EFG is made up of the same two lines and is equal to 90 degrees (shown by the little box) so <EFD must be equivalent.
To find the solution, simply take 3 and divide it by 12. 3/12 as a fraction would be simplified down to 1/4 or 0.25. Therefore, each student would receive one quarter of a pizza.
1/2 of 14 is 7. multiply 14/1 to 1/2.
