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3 years ago

4=x^2-7 solve each equation

Mathematics

2 answers:

jolli1 [7]3 years ago

8 0

Answer:

√11

Step-by-step explanation:

4 = x^2 -7

Add 7 to both sides

11 = x^2

Square root both sides

√11 = x

Allushta [10]3 years ago

8 0

Answer:

x= 3.31 or (square root) of 11

Step-by-step explanation:

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7nadin3 [17]

Answer:

Step-by-step explanation:

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3 years ago

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myrzilka [38]

100 ounces = 6.25 pints

A mile unit is equal to 1760 yards. inches =mile * 63360 2*63360=126720

2 Miles = 126720 Inches

There are 36 inches in a yard

3600/36= 100

3600 inches = 100 yards

1 m = 1/1000 km

6800/1000 = 6.8

6800 m = 6.8 km

1 m = 100 cm

15000/100=150

15000 cm=150 m

a) Johnson ran yard in second= 9

1 minute = 60 second

Johnson ran yard in one minute= 9 *60= 540 yards

b) Johnson ran yard in second= 9

1 hour = 60 minutes *60 second= 1200 seconds

Johnson ran yard in one hour= 9 *1200= 10,800 yards

c) Johnson ran yard in one hour= 9 *1200= 10,800 yards

1 mile = 1760 yards

miles did he run in one hour= 10,800 / 1760 =6

Johnson ran 6 mile in one hour

5 0

3 years ago

I don’t know how to solve this

LuckyWell [14K]

Answer:

(3x-5)x(3x+5)

Step-by-step explanation:

Calcula el producto

7 0

3 years ago

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Add the numerator and denominator seperatly, then find the quotient <br> -3( - 8) / 5 + 7

Aleonysh [2.5K]

Numerator = -3( - 8) = - 3 - 8 = -11

Denominator = 5 + 7 = 12

So the quotient = -11/12

Answer

- 11/12

4 0

3 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0

3 years ago