Help quickly please!

What is 30xy -28xy -xy in simple form

Ad libitum [116K]

Answer:

1xy

Step-by-step explanation:

30xy-28xy=2xy-xy=xy or 1xy

4 0

3 years ago

A used CD is a dollar more than one third the price of a new CD. If a new CD costs $18, how much is a used CD

Veseljchak [2.6K]

Answer:

6

Step-by-step explanation:

8 0

3 years ago

a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou

Fed [463]

Answer:

$\displaystyle P(A)=\frac{6}{11}$

Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

$\Omega=\{WW,WN,NW,NN\}$

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

$A=\{WN,NW\}$

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

$\displaystyle \frac{5}{11}$

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

$\displaystyle \frac{6}{10}$

Thus the option WN has the probability

$\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}$

Now for the second option NW. The initial probability to pick a non-white counter is

$\displaystyle \frac{6}{11}$

The probability to pick a white counter is

$\displaystyle \frac{5}{10}$

Thus the option NW has the probability

$\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}$

The total probability of event A is the sum of both

$\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}$

$\boxed{\displaystyle P(A)=\frac{6}{11}}$

7 0

3 years ago

A random number from 1 to 5 is selected

shutvik [7]

Answer:

Relative frequency of selecting a 2 = 8/50 = 0.16

Relative frequency of selecting a 3 = 14/50 = 0.28

Step-by-step explanation:

When we have a given experiment with given outcomes (such that each time that we perform the experiment, one outcome happens) the relative frequency of a given outcome is the quotient between the number of times that that outcome happened, and the total number of times that the experiment was performed.

Here the experiment is selecting a random number between 1 and 5, and it is performed 50 times.

Out of these 50 times, the outcome "2" appears 8 times.

Then the relative frequency of selecting the number 2 is:

f(2) = 8/50 = 0.16

And of these 50 experiments, the outcome "3" appears 14 times.

Then the relative frequency of selecting the number 3 is:

f(3) = 14/50 = 0.28

7 0

3 years ago

What is the rate of change between the points (0,5) and (1,-1)?

erastova [34]

Answer:

Rate of change (slope) = - 6

Step-by-step explanation:

(-1-5)/(1-0) = -6/1 = -6

6 0

3 years ago