Answer:
<h2><em><u>Pythagorean </u></em><em><u>theorem </u></em><em><u>reads </u></em><em><u>as:</u></em></h2>
<h2><em><u>H²</u></em><em><u>=</u></em><em><u>P²</u></em><em><u>+</u></em><em><u>B</u></em><em><u>²</u></em></h2>
<h2><em><u>in </u></em><em><u>which </u></em><em><u>p </u></em><em><u>reads </u></em><em><u>as </u></em><em><u>perpendicular </u></em><em><u>so </u></em></h2>
<h2><em><u>P²</u></em><em><u>=</u></em><em><u>H²</u></em><em><u>-</u></em><em><u>B²</u></em></h2>
<em><u>
</u></em>
Answer:
yes, the student who has 8 pets.
Step-by-step explanation:
the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"
Answer: 8
Step-by-step explanation:
6x-3=45
6x=48
x=8
2x is what I would say but i sayy ask an expert
Answer:
2592 cm
Step-by-step explanation:
square area = x²
rectangle area = bh
so
x² = bh
since the areas are equal
b and h are in the problem as 64 and 81
x² = 64x81
x² = 5184
divide by 2
x = 2592 cm