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Natalija [7]
4 years ago
8

How much is 1 1/4 + 3/4 + 1 1/3 step by step

Mathematics
1 answer:
dangina [55]4 years ago
3 0

Answer:

  3 1/3

Step-by-step explanation:

<u>Step 1</u> is to look at the problem.

Here, you notice that the first two numbers have fractions that are quarters. The total of those two fractions is 1/4 + 3/4 = 4/4 = 1.

So, the sum of the first two numbers is ...

  1 1/4 + 3/4 = 1 +(1/4 +3/4) = 1 +1 = 2

<u>Step 2</u> is to add the next mixed number, which has a fraction with a different denominator. Since you have no fractions to add at this point, the sum is just ...

  2 + 1 1/3 = 3 1/3

_____

<em>Comment on adding fractions</em>

Generally, adding fractions requires you determine a common denominator. Often, you are asked to find the <em>least</em> common denominator, but that isn't necessary. Sometimes that can save the work of reducing the fraction that results, but sometimes it makes more work.

Here, a common denominator for fourths and thirds would be twelfths:

  1/4 = 3/12

  1/3 = 4/12

However, since adding the fourths results in an integer, no common denominator is necessary.

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The answer to the question is d, 4
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4 years ago
The perimeter of a rectangle is 40 inches. The table shows some of the possible dimensions for the length and area of the rectan
Mama L [17]

Answer:

Therefore the Dimensions are

Length =18 inches and Width = 2 inches

OR

Length =2 inches and Width = 18 inches

Step-by-step explanation:

Let the Width of rectangle be 'W' inches.

The length of a rectangle  be 'L' inches.

Area of rectangle given is 36 square inches.

Perimeter of Rectangle is 40 inches.

To Find:

Length = L = ?

Width = W = ?

Solution:

Perimeter of Rectangle is given as

\textrm{Perimeter of Rectangle}=2\times (Length +Width)

Substituting we get

40=2(L+W)\\\\L+W=20\\\therefore L=20-W

We have area of rectangle given as

\textrm{Area of Rectangle}=Length\times Width)

Substituting the given values we get

36=(20-W)\times W\\W^{2}-20W+36=0

Which is a Quadratic Equation, So by Splitting the middle term we get

W^{2}-18W-2W+36=0\\W(W-18)-2(W-18)=0\\(W-2)(W-18)=0\\\therefore W=2\ inches\ or\ W =18\ inches

Therefore the Length will be

L=20-W=20-2=18\ inches\\OR\\L=20-18=2\ inches

Therefore the Dimensions are

Length =18 inches and Width = 2 inches

OR

Length =2 inches and Width = 18 inches

7 0
3 years ago
In triangle JKL and triangle PQR line JK = PQR line KL equals QR angle K equal angle Q then JKL must be congruent triangle PQR
Bess [88]
Answer - TRUE

Based on the information given above, we can prove that triangle <span>JKL is congruent to triangle PQR based on the SAS postulate. In other words, since </span>two sides (JK and KL) and the included angle (K) of triangle JKR are congruent<span> to two sides (PQ and QR) and the included angle (Q) of triangle PQR, then triangle </span><span>JKL must be congruent to triangle PQR.</span>
8 0
4 years ago
Read 2 more answers
kareem took 5 hours to drive 470km from Sudbury to Brantford. for part of the trip he drove at 100km/h. for the rest of the trip
alexira [117]

Answer:

He drove 200 km at 100 km/h and 270 km at 90 km/h

Step-by-step explanation:

Distance = Speed × Time

<em>Assume that Kareem drove at 100 km/h for x hour</em>

∵ Kareem drove at 100 km/h for x hours

∴ He drove a distance = 100 × x

∴ He drove a distance = 100 x km

∵ He took 5 hours in whole trip

- Subtract x from 5 to find the time that he took in the rest

   of the trip

∴ The time of the rest of the trip = 5 - x hours

∵ For the rest of the trip he drove at 90 km/h

∴ He drove a distance = 90 × (5 - x)

∴ He drove a distance = 450 - 90 x

∵ He drove 470 km in whole trip

- Add the two distance and equate the sum by 470

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- Add the like terms in the left hand side

∴ 10 x + 450 = 470

- Subtract 450 from both sides

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- Divide both sides by 10

∴ x = 2

<em>Substitute the value of x in each distance to find the distance of each part</em>

∵ The distance of the first part = 100 x

∴ The distance of the first part = 100(2)

∴ The distance of the first part = 200 km

∵ The distance of the second part = 450 - 90 x

∴ The distance of the second part = 450 - 90(2) = 450 - 180

∴ The distance of the second part = 270 km

He drove 200 km at 100 km/h and 270 km at 90 km/h

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3 years ago
TRUE OR FALSE QUESTION
stira [4]

That's false.  p(x) can have any number of linear factors (one or more).

p(x) = x(x+1)(x+2)(x+3)

has p(-3)=0 and four linear factors.

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4 years ago
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