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AVprozaik [17]
2 years ago
5

What is the approximate area of the triangle below? 95 degrees 35 degrees 14cm.

Mathematics
1 answer:
svp [43]2 years ago
4 0

By utilizing the law of the sines and Heron's formula, we find that the <em>approximate</em> area of the triangle is approximately 73.1 square centimeters. (Correct choice: A)

<h3>How to calculate the area of a triangle by Heron's formula</h3>

Prior to using Heron's formula, we must find the lengths of the missing sides by law of the sines:

A = 180° - 95° - 35°

A = 50°

b = 14\,cm \times \frac{\sin 35^{\circ}}{\sin 50^{\circ}}

b ≈ 10.483 cm

c = 14\,cm \times \frac{\sin 95^{\circ}}{\sin 50^{\circ}}

c ≈ 18.206 cm

Now, we proceed to calculate the area of the triangle:

s = 0.5 · (14 cm + 10.483 cm + 18.206 cm)

s = 21.345 cm

A = \sqrt{(21.345\, cm) \cdot (21.345\, cm - 14\,cm)\cdot (21.345\, cm - 10.483\,cm)\cdot (21.345\,cm - 18.206\,cm)}

A ≈ 73.113 cm²

By utilizing the law of the sines and Heron's formula, we find that the <em>approximate</em> area of the triangle is approximately 73.1 square centimeters. (Correct choice: A)

To learn more on triangles: brainly.com/question/2773823

#SPJ1

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Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

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ahora queremos saber cuantas cajas (x) equivalen a 7653kg

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Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

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La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

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Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

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