The union of the sets are the values that appear in both sets when plotted in a Venn diagram and if I'm not mistaking, I think the right answer is (B)
Answer:
- 127.3
- 52.7
- 127.3
- 52.7
Step-by-step explanation:
Since we know the angle measure of angle 4, we already know that angle 2 will have the same measure according to do the vertical angle theorem. Now to find angles 1 and 3, we can make an equation and solve for x (supplementary angles).
52.7 + x = 180
x = 127.3
Best of Luck!
Answer:
The surface area of right regular hexagonal pyramid = 82.222 cm³
Step-by-step explanation:
Given as , for regular hexagonal pyramid :
The of base side = 3 cm
The slant heights = 6 cm
Now ,
The surface area of right regular hexagonal pyramid = 
Where a is the base side
And h is the slant height
So, The surface area of right regular hexagonal pyramid = 
Or, The surface area of right regular hexagonal pyramid = 
Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 ×
∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538
I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842
So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer
<h3>
Answer ↓</h3>
<h3>
Calculations ↓</h3>
In order to make a the subject of this equation , we need to get a by itself .
The current equation is :
v = u + at
Subtract u on both sides :
v-u=at
Now, divide by t on both sides :
v-u/t=a
<h3>So the formula looks like ↓</h3>

hope helpful ~
H=vt-16t²
vt-16t²=H
vt=16t²+H
v=(16t²+H)/t
v=16(t²/t)+H/t
v=16t+H/t
Answer: the answer would be: v=16t+H/t