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mina [271]
3 years ago
6

1/x<4x

; 4x" alt=" \frac{1}{x} < 4x" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
liraira [26]3 years ago
6 0

Answer:

x>\frac{1}{2} \\x

Step-by-step explanation:

If we solve for 'x' variable, its recommended to multiply 'x' variable in both sides of inequality:

we have \frac{1}{4}< x^{2} \\

This is a quadratic equation, two answer are going to be obtained from here.

since \sqrt{x^{2} } = |x|

Applying square roots to both sides of inequality sign we wil have the following

\sqrt{\frac{1}{4} } < \sqrt{x^{2} }

This leaves to the following

\frac{1}{4}

remember that |x|= +/ - x

so

x>\frac{1}{2} \\x

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Answer:

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Step-by-step explanation:

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3 years ago
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The translation of a segment or object, from one location to another on the plane, doesn't change its length, just its location.

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3 years ago
AB is congruent to DE because segment DE was constructed so that DE = AB. BC is congruent to EF because segment EF was construct
Alex Ar [27]

DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

<h3>Congruent shape</h3>

Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.

Given that DE = AB and BC = EF.

In right triangle DEF, using Pythagoras:

DF² = DE² + EF²

Also, In right triangle ABC, using Pythagoras:

AC² = AB² + BC²

But DE = AB and EF = BC, hence:

AC² = DE² + EF²

AC² = DF²

Taking square root of both sides, hence:

AC = DF

Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

Find out more on Congruent shape at: brainly.com/question/11329400

6 0
2 years ago
Simplify the difference quotient f(x)=x^2+9
Setler [38]

Answer:

sorry is its complicated

Step-by-step explanation:

Find the components of the definition.

f

(

x

+

h

)

=

x

2

+

2

h

x

+

h

2

−

9

f

(

x

)

=

x

2

−

9

Plug in the components.

f

(

x

+

h

)

−

f

(

x

)

h

=

x

2

+

2

h

x

+

h

2

−

9

−

(

x

2

−

9

)

h

8 0
3 years ago
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