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3 years ago

The number 9 is what percent of the number 72 ?

Mathematics

2 answers:

nikdorinn [45]3 years ago

7 0

Answer:12.5% of 72 is 9

Step-by-step explanation:

prisoha [69]3 years ago

4 0

Answer:

I personally disagree with the answer the person above me has given.

Step-by-step explanation:

since 7.2 = 10% of 72 we will again find out ten percent of that number which is 0.72. 7.2-0.72=6.48% or if we round it 6.5%

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3 years ago

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telo118 [61]

Answer:

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Step-by-step explanation:

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3 years ago

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iragen [17]

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Answer:

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Step-by-step explanation:

The triangle inequality requires the sum of the two shortest sides exceed the longest side.

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x + 14 > 15

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When 14 and 15 are the shortest:

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_____

Additional comment

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2 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

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3 years ago